Express as a function of a DIFFERENT angle, 0^(@) <= theta < 360^(@). cos(88^(@)) cos(◻^(@))

Identify Related Angle: Identify a related angle to 88° that can simplify the expression. Since 88° is close to 90°, we can use the fact that cos(90° - θ) = sin(θ). Here, θ would be 90° - 88° = 2°.Apply Co-Function Identity: Apply the co-function identity to express cos(88°) in terms of sine. Using the identity from Step 1, we have cos(88°) = sin(90° - 88°) = sin(2°).Verify Range: Verify that the new expression is within the required range. Since 2° is within the range 0° ≤ theta < 360°, we have successfully expressed cos(88°) as a function of a different angle.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Express as a function of a DIFFERENT angle,
0^(@) <= theta < 360^(@).

cos(88^(@))

cos(◻^(@))

Express as a function of a DIFFERENT angle, 0^{\circ} \leq \theta<360^{\circ} . $\newline$ $\cos \left(88^{\circ}\right)$ $\newline$ $\cos \left(\square^{\circ}\right)$

View step-by-step help

Home

Math Problems

Algebra 2

Sin, cos, and tan of special angles

Full solution

Q. Express as a function of a DIFFERENT angle,

0^{\circ} \leq \theta<360^{\circ}

\newline

\cos \left(88^{\circ}\right)

\newline

\cos \left(\square^{\circ}\right)

Identify Related Angle: Identify a related angle to $88°$ that can simplify the expression. $\newline$ Since $88°$ is close to $90°$ , we can use the fact that $\cos(90° - \theta) = \sin(\theta)$ . Here, $\theta$ would be $90° - 88° = 2°$ .
Apply Co-Function Identity: Apply the co-function identity to express $\cos(88°)$ in terms of sine. $\newline$ Using the identity from Step $1$ , we have $\cos(88°) = \sin(90° - 88°) = \sin(2°)$ .
Verify Range: Verify that the new expression is within the required range. $\newline$ Since $2^\circ$ is within the range 0^\circ \leq \theta < 360^\circ, we have successfully expressed $\cos(88^\circ)$ as a function of a different angle.