Express as a function of a DIFFERENT angle, 0^(@) <= theta < 360^(@). sin(128^(@)) sin(◻^(@))

Identify Reference Angle: Identify the reference angle for 128°. The reference angle is the acute angle formed by the terminal side of the given angle and the horizontal axis. Since 128° is in the second quadrant, where sine is positive, the reference angle is 180° - 128°. Calculation: 180° - 128° = 52°Express in Terms of Reference Angle: Express sin(128°) in terms of its reference angle. Since 128° is in the second quadrant and sine is positive in the second quadrant, sin(128°) is equal to sin(52°). Therefore, sin(128°) = sin(52°).Check Answer Prompt: Check if the expression answers the question prompt. The question prompt asks to express sin(128°) as a function of a different angle within the range 0° ≤ theta < 360°. Since 52° is within this range and sin(128°) has been expressed as sin(52°), the question prompt has been answered.

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Express as a function of a DIFFERENT angle,
0^(@) <= theta < 360^(@).

sin(128^(@))

sin(◻^(@))

Express as a function of a DIFFERENT angle, 0^{\circ} \leq \theta<360^{\circ} . $\newline$ $\sin \left(128^{\circ}\right)$ $\newline$ $\sin \left(\square^{\circ}\right)$

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Algebra 2

Sin, cos, and tan of special angles

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Q. Express as a function of a DIFFERENT angle,

0^{\circ} \leq \theta<360^{\circ}

\newline

\sin \left(128^{\circ}\right)

\newline

\sin \left(\square^{\circ}\right)

Identify Reference Angle: Identify the reference angle for $128°$ . The reference angle is the acute angle formed by the terminal side of the given angle and the horizontal axis. Since $128°$ is in the second quadrant, where sine is positive, the reference angle is $180° - 128°$ . Calculation: $180° - 128° = 52°$
Express in Terms of Reference Angle: Express $\sin(128°)$ in terms of its reference angle. $\newline$ Since $128°$ is in the second quadrant and sine is positive in the second quadrant, $\sin(128°)$ is equal to $\sin(52°)$ . $\newline$ Therefore, $\sin(128°) = \sin(52°)$ .
Check Answer Prompt: Check if the expression answers the question prompt. $\newline$ The question prompt asks to express $\sin(128^\circ)$ as a function of a different angle within the range 0^\circ \leq \theta < 360^\circ. Since $52^\circ$ is within this range and $\sin(128^\circ)$ has been expressed as $\sin(52^\circ)$ , the question prompt has been answered.