Express as a function of a DIFFERENT angle, 0^(@) <= theta < 360^(@). tan(98^(@)) tan(◻^(@))

Identify Reference Angle: Identify the reference angle for 98° in the unit circle. Since 98° is in the second quadrant where tangent is positive, we need to find the acute angle that is associated with 98°. The reference angle is the difference between 98° and 180°, which is the straight line angle in the second quadrant. Reference angle = 180° - 98° = 82°.Determine Tangent Sign: Determine the sign of the tangent function in the second quadrant. In the second quadrant, the sine function is positive and the cosine function is negative. Since tangent is sine over cosine, tan(θ) will be positive in the second quadrant.Express as Function: Express tan(98°) as a function of the reference angle. Since tan(θ) is positive in the second quadrant and we have found the reference angle to be 82°, we can express tan(98°) as tan(82°).

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Express as a function of a DIFFERENT angle,
0^(@) <= theta < 360^(@).

tan(98^(@))

tan(◻^(@))

Express as a function of a DIFFERENT angle, 0^{\circ} \leq \theta<360^{\circ} . $\newline$ $\tan \left(98^{\circ}\right)$ $\newline$ $\tan \left(\square^{\circ}\right)$

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Algebra 2

Find trigonometric ratios using reference angles

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Q. Express as a function of a DIFFERENT angle,

0^{\circ} \leq \theta<360^{\circ}

\newline

\tan \left(98^{\circ}\right)

\newline

\tan \left(\square^{\circ}\right)

Identify Reference Angle: Identify the reference angle for $98°$ in the unit circle. $\newline$ Since $98°$ is in the second quadrant where tangent is positive, we need to find the acute angle that is associated with $98°$ . The reference angle is the difference between $98°$ and $180°$ , which is the straight line angle in the second quadrant. $\newline$ Reference angle = $180° - 98° = 82°$ .
Determine Tangent Sign: Determine the sign of the tangent function in the second quadrant. $\newline$ In the second quadrant, the sine function is positive and the cosine function is negative. Since tangent is sine over cosine, $\tan(\theta)$ will be positive in the second quadrant.
Express as Function: Express $\tan(98°)$ as a function of the reference angle. $\newline$ Since $\tan(\theta)$ is positive in the second quadrant and we have found the reference angle to be $82°$ , we can express $\tan(98°)$ as $\tan(82°)$ .