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Express as a function of a DIFFERENT angle, 
0^(@) <= theta < 360^(@).

sin(218^(@))

sin(◻^(@))

Express as a function of a DIFFERENT angle, 0^{\circ} \leq \theta<360^{\circ} .\newlinesin(218) \sin \left(218^{\circ}\right) \newlinesin() \sin \left(\square^{\circ}\right)

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Q. Express as a function of a DIFFERENT angle, 0θ<360 0^{\circ} \leq \theta<360^{\circ} .\newlinesin(218) \sin \left(218^{\circ}\right) \newlinesin() \sin \left(\square^{\circ}\right)
  1. Understand the problem: Understand the problem.\newlineWe need to express sin(218)\sin(218^\circ) as a function of a different angle, which is typically done by finding an equivalent angle within the standard range of 00^\circ to 360360^\circ that has the same sine value.
  2. Find the reference angle: Find the reference angle.\newlineThe reference angle is the acute angle that the given angle makes with the x-axis. Since 218°218° is in the third quadrant, we subtract it from 180°180° to find the reference angle.\newlineReference angle = 218°180°=38°218° - 180° = 38°.
  3. Determine equivalent angle: Determine the equivalent angle with the same sine value.\newlineSince sine is positive in the first and second quadrants, and 218218^\circ is in the third quadrant, we need to find an angle in the first or second quadrant that has the same sine value as 3838^\circ. The equivalent angle in the second quadrant is 18038=142180^\circ - 38^\circ = 142^\circ.
  4. Express in terms of equivalent angle: Express sin(218°)\sin(218°) in terms of the equivalent angle.\newlineWe can now express sin(218°)\sin(218°) as sin(142°)\sin(142°) because they have the same sine value.

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