Given that l=2r+(1)/(2)pi r, make r the subject of the relation.

Write Relation: Write down the given relation. We are given the relation l = 2r + (1/2)πr. We need to make r the subject of this relation.Factor Out r: Factor out r from the right side of the equation. We can factor r out of the terms on the right side to get l = r(2 + (1/2)π).Isolate r: Isolate r by dividing both sides of the equation by (2 + (1/2)π). To solve for r, we divide both sides by the factor that is multiplied by r, which is (2 + (1/2)π). So we get r = l / (2 + (1/2)π).Simplify Expression: Simplify the expression if possible. The expression for r is already in its simplest form, so no further simplification is needed.Check for Errors: Check for any mathematical errors. There are no mathematical errors in the steps taken to isolate r.

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Given that l=2r+(1)/(2)pi r, make r the subject of the relation.

Given that $l=2 r+\frac{1}{2} \pi r$ , make $r$ the subject of the relation.

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Algebra 1

Domain and range of square root functions: equations

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Q. Given that

l=2 r+\frac{1}{2} \pi r

, make

r

the subject of the relation.

Write Relation: Write down the given relation. $\newline$ We are given the relation $l = 2r + (\frac{1}{2})\pi r$ . We need to make $r$ the subject of this relation.
Factor Out r: Factor out $r$ from the right side of the equation. $\newline$ We can factor $r$ out of the terms on the right side to get $l = r(2 + (\frac{1}{2})\pi)$ .
Isolate $r$ : Isolate $r$ by dividing both sides of the equation by $(2 + (1/2)\pi)$ . To solve for $r$ , we divide both sides by the factor that is multiplied by $r$ , which is $(2 + (1/2)\pi)$ . So we get $r = l / (2 + (1/2)\pi)$ .
Simplify Expression: Simplify the expression if possible. $\newline$ The expression for $r$ is already in its simplest form, so no further simplification is needed.
Check for Errors: Check for any mathematical errors. $\newline$ There are no mathematical errors in the steps taken to isolate $r$ .