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Evaluate the summation below.

sum_(t=0)^(4)(-t^(2)+4t)
Answer:

Evaluate the summation below.\newlinet=04(t2+4t) \sum_{t=0}^{4}\left(-t^{2}+4 t\right) \newlineAnswer:

Full solution

Q. Evaluate the summation below.\newlinet=04(t2+4t) \sum_{t=0}^{4}\left(-t^{2}+4 t\right) \newlineAnswer:
  1. Write General Term: Write down the general term of the series to be summed, which is given by the expression t2+4t -t^2 + 4t .
  2. Calculate Values: Calculate the value of the general term for each value of tt from 00 to 44 and sum them up.\newlineFor t=0t=0: (02+40)=0(-0^2 + 4\cdot0) = 0\newlineFor t=1t=1: (12+41)=1+4=3(-1^2 + 4\cdot1) = -1 + 4 = 3\newlineFor t=2t=2: (22+42)=4+8=4(-2^2 + 4\cdot2) = -4 + 8 = 4\newlineFor t=3t=3: 0000\newlineFor 0011: 0022
  3. Add Values: Add up the values obtained for each tt to find the sum of the series.Sum=0+3+4+3+0=10\text{Sum} = 0 + 3 + 4 + 3 + 0 = 10

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