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Evaluate the summation below.

sum_(n=0)^(4)(6n^(2)-8n)
Answer:

Evaluate the summation below.\newlinen=04(6n28n) \sum_{n=0}^{4}\left(6 n^{2}-8 n\right) \newlineAnswer:

Full solution

Q. Evaluate the summation below.\newlinen=04(6n28n) \sum_{n=0}^{4}\left(6 n^{2}-8 n\right) \newlineAnswer:
  1. Identify series and range: Identify the series to be summed and the range of the summation.\newlineWe are given the series 6n28n6n^2 - 8n and we need to sum it from n=0n=0 to n=4n=4.
  2. Evaluate series at each n: Evaluate the series at each value of nn from 00 to 44 and sum the results.\newlineFor n=0n=0: 6(0)28(0)=06(0)^2 - 8(0) = 0\newlineFor n=1n=1: 6(1)28(1)=68=26(1)^2 - 8(1) = 6 - 8 = -2\newlineFor n=2n=2: 6(2)28(2)=2416=86(2)^2 - 8(2) = 24 - 16 = 8\newlineFor n=3n=3: 0000\newlineFor 0011: 0022\newlineNow, sum these results: 0033.
  3. Perform addition to find sum: Perform the addition to find the sum of the series. \newline0+(2)+8+30+64=02+8+30+64=1000 + (-2) + 8 + 30 + 64 = 0 - 2 + 8 + 30 + 64 = 100

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