Evaluate the summation below. 4sum_(p=0)^(3)(9p-2p^(2)) Answer:

Substitute Values: Write down the series explicitly by substituting the values of p from 0 to 3 into the expression (9p - 2p^2). For p = 0: (9*0 - 2*0^2) = 0 For p = 1: (9*1 - 2*1^2) = 9 - 2 = 7 For p = 2: (9*2 - 2*2^2) = 18 - 8 = 10 For p = 3: (9*3 - 2*3^2) = 27 - 18 = 9Calculate Sum: Add the results of the series to find the sum. Sum = 0 + 7 + 10 + 9 Sum = 26Multiply by 4: Multiply the sum by 4, as indicated by the 4 in front of the summation symbol. Final Answer = 4 * Sum Final Answer = 4 * 26 Final Answer = 104

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Evaluate the summation below.

4sum_(p=0)^(3)(9p-2p^(2))
Answer:

Evaluate the summation below. $\newline$ $4 \sum_{p=0}^{3}\left(9 p-2 p^{2}\right)$ $\newline$ Answer:

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Algebra 2

Sum of finite series starts from 1

Full solution

Q. Evaluate the summation below.

\newline

4 \sum_{p=0}^{3}\left(9 p-2 p^{2}\right)

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Answer:

Substitute Values: Write down the series explicitly by substituting the values of $p$ from $0$ to $3$ into the expression $(9p - 2p^2)$ . $\newline$ For $p = 0$ : $(9\times 0 - 2\times 0^2) = 0$ $\newline$ For $p = 1$ : $(9\times 1 - 2\times 1^2) = 9 - 2 = 7$ $\newline$ For $p = 2$ : $(9\times 2 - 2\times 2^2) = 18 - 8 = 10$ $\newline$ For $0$ $0$ : $0$ $1$
Calculate Sum: Add the results of the series to find the sum. $\newline$ Sum = $0 + 7 + 10 + 9$ $\newline$ Sum = $26$
Multiply by $4$ : Multiply the sum by $4$ , as indicated by the $4$ in front of the summation symbol. $\newline$ Final Answer = $4 \times \text{Sum}$ $\newline$ Final Answer = $4 \times 26$ $\newline$ Final Answer = $104$