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Let’s check out your problem:
Evaluate the expression for
w
=
16
w = 16
w
=
16
. Simplify your answer.
\newline
w
−
16
w
=
w - \frac{16}{w} =
w
−
w
16
=
_____
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Math Problems
Algebra 2
Evaluate rational expressions II
Full solution
Q.
Evaluate the expression for
w
=
16
w = 16
w
=
16
. Simplify your answer.
\newline
w
−
16
w
=
w - \frac{16}{w} =
w
−
w
16
=
_____
Identify Expression:
Identify the expression after substituting
w
=
16
w = 16
w
=
16
Substitute
16
16
16
for
w
w
w
in
w
−
16
w
w − \frac{16}{w}
w
−
w
16
.
(
16
−
16
16
)
(16 − \frac{16}{16})
(
16−
16
16
)
Substitute and Simplify:
Evaluate
16
16
\frac{16}{16}
16
16
\newline
16
16
\frac{16}{16}
16
16
equals
1
1
1
because any number divided by itself is
1
1
1
.
\newline
Numerator:
16
16
16
\newline
Denominator:
1
1
1
Evaluate Division:
Subtract
16
16
\frac{16}{16}
16
16
from
16
16
16
\newline
16
−
1
16 - 1
16
−
1
equals
15
15
15
because when you subtract
1
1
1
from
16
16
16
, you get
15
15
15
.
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\newline
1
7
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÷
4
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=
1 \frac{7}{9} \div \frac{4}{5}=
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\newline
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÷
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Divide. Write the quotient in lowest terms.
\newline
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Divide. Write the quotient in lowest terms.
\newline
4
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5
÷
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=
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Divide. Write the quotient in lowest terms.
\newline
2
1
2
÷
2
2
3
=
2 \frac{1}{2} \div 2 \frac{2}{3}=
2
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Question
Divide. Write the quotient in lowest terms.
\newline
3
3
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÷
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=
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3
8
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Question
Divide. Write the quotient in lowest terms.
\newline
3
3
10
÷
1
4
7
=
3 \frac{3}{10} \div 1 \frac{4}{7}=
3
10
3
÷
1
7
4
=
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Question
Divide. Write the quotient in lowest terms.
\newline
4
2
3
÷
7
=
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4
3
2
÷
7
=
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Question
d
d
x
[
8
x
2
+
2
x
−
3
]
=
?
\frac{d}{d x}\left[\sqrt{8 x^{2}+2 x-3}\right]=?
d
x
d
[
8
x
2
+
2
x
−
3
]
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
8
x
+
1
8
x
2
+
2
x
−
3
\frac{8 x+1}{\sqrt{8 x^{2}+2 x-3}}
8
x
2
+
2
x
−
3
8
x
+
1
\newline
(B)
8
x
+
1
x
\frac{8 x+1}{\sqrt{x}}
x
8
x
+
1
\newline
(c)
16
x
+
2
\sqrt{16 x+2}
16
x
+
2
\newline
(D)
1
2
16
x
+
2
\frac{1}{2 \sqrt{16 x+2}}
2
16
x
+
2
1
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Posted 9 months ago
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