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Let’s check out your problem:
Evaluate the expression for
w
=
10
w = 10
w
=
10
. Simplify your answer.
\newline
w
w
−
8
=
\frac{w}{w} - 8 =
w
w
−
8
=
_____
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Math Problems
Algebra 2
Evaluate rational expressions II
Full solution
Q.
Evaluate the expression for
w
=
10
w = 10
w
=
10
. Simplify your answer.
\newline
w
w
−
8
=
\frac{w}{w} - 8 =
w
w
−
8
=
_____
Identify Expression:
Identify the expression after substituting
w
=
10
w = 10
w
=
10
\newline
Substitute
10
10
10
for
w
w
w
in
w
w
−
8
\frac{w}{w} − 8
w
w
−8
.
\newline
(
10
10
)
−
8
(\frac{10}{10}) − 8
(
10
10
)
−8
Substitute and Simplify:
Evaluate
10
/
10
10/10
10/10
\newline
10
/
10
10/10
10/10
equals
1
1
1
because any number divided by itself is
1
1
1
.
\newline
Numerator:
1
1
1
Evaluate Division:
Subtract
8
8
8
from
1
1
1
\newline
1
−
8
1 − 8
1−8
equals
−
7
-7
−
7
.
Subtract Numbers:
Write the final answer
\newline
The expression simplifies to
−
7
-7
−
7
.
More problems from Evaluate rational expressions II
Question
Divide. Write the quotient in lowest terms.
\newline
1
7
9
÷
4
5
=
1 \frac{7}{9} \div \frac{4}{5}=
1
9
7
÷
5
4
=
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Divide. Write the quotient in lowest terms.
\newline
1
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Question
Divide. Write the quotient in lowest terms.
\newline
1
1
4
÷
1
2
5
=
1 \frac{1}{4} \div 1 \frac{2}{5}=
1
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÷
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2
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Question
Divide. Write the quotient in lowest terms.
\newline
5
8
÷
1
1
3
=
\frac{5}{8} \div 1 \frac{1}{3}=
8
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÷
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Question
Divide. Write the quotient in lowest terms.
\newline
4
4
5
÷
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2
=
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4
5
4
÷
1
2
1
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Question
Divide. Write the quotient in lowest terms.
\newline
2
1
2
÷
2
2
3
=
2 \frac{1}{2} \div 2 \frac{2}{3}=
2
2
1
÷
2
3
2
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Question
Divide. Write the quotient in lowest terms.
\newline
3
3
8
÷
9
=
3 \frac{3}{8} \div 9=
3
8
3
÷
9
=
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Question
Divide. Write the quotient in lowest terms.
\newline
3
3
10
÷
1
4
7
=
3 \frac{3}{10} \div 1 \frac{4}{7}=
3
10
3
÷
1
7
4
=
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Question
Divide. Write the quotient in lowest terms.
\newline
4
2
3
÷
7
=
4 \frac{2}{3} \div 7=
4
3
2
÷
7
=
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Posted 10 months ago
Question
d
d
x
[
8
x
2
+
2
x
−
3
]
=
?
\frac{d}{d x}\left[\sqrt{8 x^{2}+2 x-3}\right]=?
d
x
d
[
8
x
2
+
2
x
−
3
]
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
8
x
+
1
8
x
2
+
2
x
−
3
\frac{8 x+1}{\sqrt{8 x^{2}+2 x-3}}
8
x
2
+
2
x
−
3
8
x
+
1
\newline
(B)
8
x
+
1
x
\frac{8 x+1}{\sqrt{x}}
x
8
x
+
1
\newline
(c)
16
x
+
2
\sqrt{16 x+2}
16
x
+
2
\newline
(D)
1
2
16
x
+
2
\frac{1}{2 \sqrt{16 x+2}}
2
16
x
+
2
1
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Posted 9 months ago
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