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Let’s check out your problem:
Evaluate the expression for
c
=
9
c = 9
c
=
9
.
\newline
Write your answer in simplest form.
\newline
c
−
8
−
c
+
10
=
\frac{c - 8}{-c + 10} =
−
c
+
10
c
−
8
=
__
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Math Problems
Algebra 2
Evaluate rational expressions II
Full solution
Q.
Evaluate the expression for
c
=
9
c = 9
c
=
9
.
\newline
Write your answer in simplest form.
\newline
c
−
8
−
c
+
10
=
\frac{c - 8}{-c + 10} =
−
c
+
10
c
−
8
=
__
Identify Expression:
Identify the expression after substituting
c
=
9
c = 9
c
=
9
\newline
Substitute
9
9
9
for
c
c
c
in the expression
c
−
8
−
c
+
10
\frac{c - 8}{-c + 10}
−
c
+
10
c
−
8
.
\newline
(
9
)
−
8
(
−
9
)
+
10
\frac{(9) - 8}{(-9) + 10}
(
−
9
)
+
10
(
9
)
−
8
Substitute and Simplify:
Evaluate
9
−
8
9 - 8
9
−
8
9
−
8
=
1
9 - 8 = 1
9
−
8
=
1
Numerator:
1
1
1
Evaluate Numerator:
Evaluate
−
9
+
10
-9 + 10
−
9
+
10
−
9
+
10
=
1
-9 + 10 = 1
−
9
+
10
=
1
Denominator:
1
1
1
Evaluate Denominator:
1
1
\frac{1}{1}
1
1
\newline
Simplify the
fraction
.
\newline
1
1
=
1
\frac{1}{1} = 1
1
1
=
1
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Evaluate the expression for
t
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4.4
t = -4.4
t
=
−
4.4
.
\newline
Write your answer in simplest form.
\newline
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\newline
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Simplify. Express your answer as a single fraction in simplest form.
\newline
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\newline
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Solve for
h
h
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\newline
−
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h
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=
−
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h
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h
−
2
−
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=
h
−
3
−
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\newline
There may be
1
1
1
or
2
2
2
solutions.
\newline
h
=
h =
h
=
_____ or
h
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Posted 1 year ago
Question
What is the equation of the vertical asymptote of
y
=
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+
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y = \frac{1}{x + 9}
y
=
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+
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? _____
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Posted 1 year ago
Question
What is the excluded value for
y
=
1
x
−
9
−
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y = \frac{1}{x - 9} - 9
y
=
x
−
9
1
−
9
?
\newline
______
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Posted 1 year ago
Question
Simplify. Write your answer using whole numbers and variables.
\newline
9
k
+
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9
k
2
+
4
k
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9
k
2
+
4
k
9
k
+
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\newline
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Posted 1 year ago
Question
Divide. Write your answer in simplest form.
\newline
g
−
1
10
g
3
+
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g
2
÷
(
g
−
1
)
\frac{g- 1}{10g^3 + 25g^2} \div (g- 1)
10
g
3
+
25
g
2
g
−
1
÷
(
g
−
1
)
\newline
______
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Posted 1 year ago
Question
Simplify. Express your answer as a single fraction in simplest form.
\newline
5
−
3
t
3
1
\frac{5 - \frac{3}{t^3}}{1}
1
5
−
t
3
3
\newline
______
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Posted 1 year ago
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