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Let’s check out your problem:
Evaluate the expression for
c
=
3
c = 3
c
=
3
.
\newline
Write your answer in simplest form.
\newline
c
−
5
−
c
−
3
=
\frac{c - 5}{-c - 3} =
−
c
−
3
c
−
5
=
__
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Math Problems
Algebra 2
Evaluate rational expressions II
Full solution
Q.
Evaluate the expression for
c
=
3
c = 3
c
=
3
.
\newline
Write your answer in simplest form.
\newline
c
−
5
−
c
−
3
=
\frac{c - 5}{-c - 3} =
−
c
−
3
c
−
5
=
__
Identify Expression:
Identify the expression after substituting
c
=
3
c = 3
c
=
3
\newline
Substitute
3
3
3
for
c
c
c
in
c
−
5
−
c
−
3
\frac{c - 5}{-c - 3}
−
c
−
3
c
−
5
.
\newline
3
−
5
−
3
−
3
\frac{3 - 5}{-3 - 3}
−
3
−
3
3
−
5
Substitute and Simplify:
Evaluate
3
−
5
3 - 5
3
−
5
\newline
3
−
5
=
−
2
3 - 5 = -2
3
−
5
=
−
2
\newline
Numerator:
−
2
-2
−
2
Evaluate Numerator:
Evaluate
−
3
−
3
-3 - 3
−
3
−
3
−
3
−
3
=
−
6
-3 - 3 = -6
−
3
−
3
=
−
6
Denominator:
−
6
-6
−
6
Evaluate Denominator:
−
2
−
6
-\frac{2}{-6}
−
−
6
2
\newline
Rewrite the
fraction
in simplest form.
\newline
Divide both
−
2
-2
−
2
and
−
6
-6
−
6
by
2
2
2
to simplify.
\newline
−
2
−
6
=
1
3
\frac{-2}{-6} = \frac{1}{3}
−
6
−
2
=
3
1
\newline
Cancel out the negative signs.
\newline
=
1
3
= \frac{1}{3}
=
3
1
More problems from Evaluate rational expressions II
Question
Divide. Write the quotient in lowest terms.
\newline
1
7
9
÷
4
5
=
1 \frac{7}{9} \div \frac{4}{5}=
1
9
7
÷
5
4
=
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Divide. Write the quotient in lowest terms.
\newline
1
4
÷
1
1
8
=
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4
1
÷
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Divide. Write the quotient in lowest terms.
\newline
1
1
4
÷
1
2
5
=
1 \frac{1}{4} \div 1 \frac{2}{5}=
1
4
1
÷
1
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2
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Question
Divide. Write the quotient in lowest terms.
\newline
5
8
÷
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3
=
\frac{5}{8} \div 1 \frac{1}{3}=
8
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÷
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Question
Divide. Write the quotient in lowest terms.
\newline
4
4
5
÷
1
1
2
=
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4
5
4
÷
1
2
1
=
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Question
Divide. Write the quotient in lowest terms.
\newline
2
1
2
÷
2
2
3
=
2 \frac{1}{2} \div 2 \frac{2}{3}=
2
2
1
÷
2
3
2
=
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Question
Divide. Write the quotient in lowest terms.
\newline
3
3
8
÷
9
=
3 \frac{3}{8} \div 9=
3
8
3
÷
9
=
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Question
Divide. Write the quotient in lowest terms.
\newline
3
3
10
÷
1
4
7
=
3 \frac{3}{10} \div 1 \frac{4}{7}=
3
10
3
÷
1
7
4
=
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Question
Divide. Write the quotient in lowest terms.
\newline
4
2
3
÷
7
=
4 \frac{2}{3} \div 7=
4
3
2
÷
7
=
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Question
d
d
x
[
8
x
2
+
2
x
−
3
]
=
?
\frac{d}{d x}\left[\sqrt{8 x^{2}+2 x-3}\right]=?
d
x
d
[
8
x
2
+
2
x
−
3
]
=
?
\newline
Choose
1
1
1
answer:
\newline
(A)
8
x
+
1
8
x
2
+
2
x
−
3
\frac{8 x+1}{\sqrt{8 x^{2}+2 x-3}}
8
x
2
+
2
x
−
3
8
x
+
1
\newline
(B)
8
x
+
1
x
\frac{8 x+1}{\sqrt{x}}
x
8
x
+
1
\newline
(c)
16
x
+
2
\sqrt{16 x+2}
16
x
+
2
\newline
(D)
1
2
16
x
+
2
\frac{1}{2 \sqrt{16 x+2}}
2
16
x
+
2
1
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Posted 9 months ago
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