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Let’s check out your problem:
Evaluate:
\newline
∑
n
=
3
5
(
n
x
+
4
)
\sum_{n=3}^{5}(n x+4)
n
=
3
∑
5
(
n
x
+
4
)
\newline
Answer:
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Home
Math Problems
Algebra 2
Evaluate rational expressions II
Full solution
Q.
Evaluate:
\newline
∑
n
=
3
5
(
n
x
+
4
)
\sum_{n=3}^{5}(n x+4)
n
=
3
∑
5
(
n
x
+
4
)
\newline
Answer:
Understand the problem:
Understand the problem We need to evaluate the sum of the expression
(
n
x
+
4
)
(n x + 4)
(
n
x
+
4
)
for
n
n
n
ranging from
3
3
3
to
5
5
5
.
Write out the terms:
Write out the terms of the sum
\newline
The sum from
n
=
3
n=3
n
=
3
to
n
=
5
n=5
n
=
5
of
(
n
x
+
4
)
(nx + 4)
(
n
x
+
4
)
means we need to calculate
(
3
x
+
4
)
+
(
4
x
+
4
)
+
(
5
x
+
4
)
(3x + 4) + (4x + 4) + (5x + 4)
(
3
x
+
4
)
+
(
4
x
+
4
)
+
(
5
x
+
4
)
.
Evaluate each term:
Evaluate each term
\newline
First term when
n
=
3
n=3
n
=
3
:
(
3
x
+
4
)
(3x + 4)
(
3
x
+
4
)
\newline
Second term when
n
=
4
n=4
n
=
4
:
(
4
x
+
4
)
(4x + 4)
(
4
x
+
4
)
\newline
Third term when
n
=
5
n=5
n
=
5
:
(
5
x
+
4
)
(5x + 4)
(
5
x
+
4
)
Add the terms together:
Add the terms together
\newline
Now we add the terms we found in Step
3
3
3
together:
\newline
(
3
x
+
4
)
+
(
4
x
+
4
)
+
(
5
x
+
4
)
(3x + 4) + (4x + 4) + (5x + 4)
(
3
x
+
4
)
+
(
4
x
+
4
)
+
(
5
x
+
4
)
Combine like terms:
Combine like terms
\newline
Combine the
x
x
x
terms:
3
x
+
4
x
+
5
x
=
12
x
3x + 4x + 5x = 12x
3
x
+
4
x
+
5
x
=
12
x
\newline
Combine the constant terms:
4
+
4
+
4
=
12
4 + 4 + 4 = 12
4
+
4
+
4
=
12
\newline
So,
(
3
x
+
4
)
+
(
4
x
+
4
)
+
(
5
x
+
4
)
=
12
x
+
12
(3x + 4) + (4x + 4) + (5x + 4) = 12x + 12
(
3
x
+
4
)
+
(
4
x
+
4
)
+
(
5
x
+
4
)
=
12
x
+
12
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\newline
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\newline
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\newline
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\newline
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\newline
g
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10
g
3
+
25
g
2
g
−
1
÷
(
g
−
1
)
\newline
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\newline
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−
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t
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1
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−
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3
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\newline
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