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Evaluate:

sum_(n=3)^(5)(nx-3)
Answer:

Evaluate:\newlinen=35(nx3) \sum_{n=3}^{5}(n x-3) \newlineAnswer:

Full solution

Q. Evaluate:\newlinen=35(nx3) \sum_{n=3}^{5}(n x-3) \newlineAnswer:
  1. Understand summation notation: Understand the summation notation. The expression n=35(nx3)\sum_{n=3}^{5}(nx-3) means we need to evaluate (nx3)(nx-3) for each integer value of nn from 33 to 55 and then sum the results.
  2. Evaluate for n=3n=3: Evaluate the expression for n=3n=3. Substitute n=3n=3 into the expression (nx3)(nx-3) to get (3x3)(3x-3).
  3. Evaluate for n=4n=4: Evaluate the expression for n=4n=4.\newlineSubstitute n=4n=4 into the expression (nx3)(nx-3) to get (4x3)(4x-3).
  4. Evaluate for n=5n=5: Evaluate the expression for n=5n=5. Substitute n=5n=5 into the expression (nx3)(nx-3) to get (5x3)(5x-3).
  5. Add results from steps: Add the results from steps 22, 33, and 44. Sum the expressions: (3x3)+(4x3)+(5x3)(3x-3) + (4x-3) + (5x-3).
  6. Combine like terms: Combine like terms.\newlineAdd the coefficients of xx and the constant terms separately: (3x+4x+5x)(3+3+3)(3x + 4x + 5x) - (3 + 3 + 3).
  7. Perform addition: Perform the addition.\newlineCalculate the sum of the coefficients of xx: 3x+4x+5x=12x3x + 4x + 5x = 12x.\newlineCalculate the sum of the constants: 333=9-3 - 3 - 3 = -9.
  8. Write final expression: Write the final expression.\newlineCombine the results from step 77 to get the final expression: 12x912x - 9.

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