Evaluate: sum_(n=0)^(2)(-4x-3n) Answer: Submit Answer

Write Terms Explicitly: Write out the terms of the series explicitly. The series is sum_(n=0)^(2)(-4x-3n), which means we need to evaluate (-4x-3n) for n=0, n=1, and n=2, and then sum these values.Evaluate for n=0,1,2: Evaluate the expression for n=0, n=1, and n=2. For n=0: (-4x-3(0)) = -4x For n=1: (-4x-3(1)) = -4x-3 For n=2: (-4x-3(2)) = -4x-6Sum Evaluated Expressions: Sum the evaluated expressions. Sum = (-4x) + (-4x-3) + (-4x-6) Sum = -4x - 4x - 3 - 4x - 6Combine Like Terms: Combine like terms. Sum = -12x - 9Check for Errors: Check for any mathematical errors in the previous steps. No errors were made in the calculations or the application of the summation.

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Evaluate:

sum_(n=0)^(2)(-4x-3n)
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Evaluate: $\newline$ $\sum_{n=0}^{2}(-4 x-3 n)$ $\newline$ Answer: $\newline$ Submit Answer

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Algebra 2

Sum of finite series starts from 1

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Q. Evaluate:

\newline

\sum_{n=0}^{2}(-4 x-3 n)

\newline

Answer:

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Write Terms Explicitly: Write out the terms of the series explicitly. $\newline$ The series is $\sum_{n=0}^{2}(-4x-3n)$ , which means we need to evaluate $(-4x-3n)$ for $n=0$ , $n=1$ , and $n=2$ , and then sum these values.
Evaluate for $n=0,1,2$ : Evaluate the expression for $n=0$ , $n=1$ , and $n=2$ . $\newline$ For $n=0$ : $(-4x-3(0)) = -4x$ $\newline$ For $n=1$ : $(-4x-3(1)) = -4x-3$ $\newline$ For $n=2$ : $(-4x-3(2)) = -4x-6$
Sum Evaluated Expressions: Sum the evaluated expressions. $\newline$ Sum = $(-4x) + (-4x-3) + (-4x-6)$ $\newline$ Sum = $-4x - 4x - 3 - 4x - 6$
Combine Like Terms: Combine like terms. $\newline$ Sum = $-12x - 9$
Check for Errors: Check for any mathematical errors in the previous steps. No errors were made in the calculations or the application of the summation.