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Evaluate:

sum_(n=0)^(2)(-4x-3n)
Answer:

Evaluate:\newlinen=02(4x3n) \sum_{n=0}^{2}(-4 x-3 n) \newlineAnswer:

Full solution

Q. Evaluate:\newlinen=02(4x3n) \sum_{n=0}^{2}(-4 x-3 n) \newlineAnswer:
  1. Evaluate Expression for n=0n=0: We need to evaluate the sum of the series for each value of nn from 00 to 22. The series is given by the expression (4x3n)(-4x-3n). Let's start by substituting n=0n=0, n=1n=1, and n=2n=2 into the expression and then summing the results.
  2. Evaluate Expression for n=1n=1: For n=0n=0, the expression becomes (4x30)(-4x-3\cdot 0) which simplifies to (4x)(-4x).
  3. Evaluate Expression for n=2n=2: For n=1n=1, the expression becomes (4x3×1)(-4x-3\times 1) which simplifies to (4x3)(-4x-3).
  4. Sum the Results: For n=2n=2, the expression becomes (4x3×2)(-4x-3\times 2) which simplifies to (4x6)(-4x-6).
  5. Combine Like Terms: Now we sum the results of the expression for n=0n=0, n=1n=1, and n=2n=2: (4x)+(4x3)+(4x6)(-4x) + (-4x-3) + (-4x-6).
  6. Final Answer: Combining like terms, we get: (4x)+(4x)+(4x)36(-4x) + (-4x) + (-4x) - 3 - 6, which simplifies to 12x9-12x - 9.
  7. Final Answer: Combining like terms, we get: (4x)+(4x)+(4x)36(-4x) + (-4x) + (-4x) - 3 - 6, which simplifies to 12x9-12x - 9.The final answer is 12x9-12x - 9.

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