Evaluate. (sqrt98)/(2^((1)/(2)))=

Apply quotient rule of radical: Apply the quotient rule of radical to (sqrt(98))/(2^(1/2)). (sqrt(98))/(2^(1/2)) = sqrt(98) / sqrt(2^2)Simplify denominator: Simplify the denominator. sqrt(2^2) = sqrt(4) = 2Find prime factorization of 98: Find the prime factorization of 98 and try to make identical pairs of factors. sqrt(98) = sqrt(2 * 7 * 7) = sqrt(2) * sqrt(7^2) = sqrt(2) * 7Combine previous results: Combine the results from the previous steps. (sqrt(98))/(2^(1/2)) = (sqrt(2) * 7) / 2Simplify expression: Simplify the expression. (sqrt(2) * 7) / 2 = (7/2) * sqrt(2)

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Evaluate. $\newline$ $\frac{\sqrt{98}}{2^{\frac{1}{2}}}=$

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Math Problems

Algebra 2

Simplify radical expressions involving fractions

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Q. Evaluate.

\newline

\frac{\sqrt{98}}{2^{\frac{1}{2}}}=

Apply quotient rule of radical: Apply the quotient rule of radical to $\frac{\sqrt{98}}{2^{\frac{1}{2}}}$ . $\frac{\sqrt{98}}{2^{\frac{1}{2}}} = \frac{\sqrt{98}}{\sqrt{2^2}}$
Simplify denominator: Simplify the denominator. $\sqrt{2^2} = \sqrt{4} = 2$
Find prime factorization of $98$ : Find the prime factorization of $98$ and try to make identical pairs of factors. $\newline$ $\sqrt{98} = \sqrt{2 \times 7 \times 7}$ $\newline$ = $\sqrt{2}$ $\times$ $\sqrt{7^2}$ $\newline$ = $\sqrt{2}$ $\times$ $7$
Combine previous results: Combine the results from the previous steps. $\newline$ $(\sqrt{98})/(2^{1/2}) = (\sqrt{2} \times 7) / 2$
Simplify expression: Simplify the expression. $(\sqrt{2} \times 7) / 2 = (7/2) \times \sqrt{2}$