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Evaluate 
int_(3)^(4)(4x^(2)-9x+1)/(x-2)dx. Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).
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Evaluate 344x29x+1x2dx \int_{3}^{4} \frac{4 x^{2}-9 x+1}{x-2} d x . Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).\newlineSubmit Answer

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Q. Evaluate 344x29x+1x2dx \int_{3}^{4} \frac{4 x^{2}-9 x+1}{x-2} d x . Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).\newlineSubmit Answer
  1. Identify Integral: Identify the integral to be evaluated.\newlineWe need to evaluate the integral of the function (4x29x+1)/(x2)(4x^2 - 9x + 1)/(x - 2) from x=3x = 3 to x=4x = 4.
  2. Polynomial Long Division: Perform polynomial long division.\newlineBefore integrating, we should simplify the integrand by performing polynomial long division of (4x29x+1)(4x^2 - 9x + 1) by (x2)(x - 2).
  3. Carry Out Division: Carry out the long division.\newlineDividing 4x24x^2 by xx gives 4x4x. Multiply (x2)(x - 2) by 4x4x to get 4x28x4x^2 - 8x. Subtract this from the original numerator to get 9x+1(8x)=x+1-9x + 1 - (-8x) = -x + 1. Dividing x-x by xx gives 1-1. Multiply (x2)(x - 2) by 1-1 to get xx22. Subtract this from xx33 to get 1-1. So the quotient is xx55 with a remainder of 1-1.
  4. Rewrite Integral: Rewrite the integral with the result of the division.\newlineThe integral can now be written as the integral of 4x14x - 1 plus the integral of the remainder 1-1 divided by (x2)(x - 2), from x=3x = 3 to x=4x = 4.\newline(4x1)dx+1(x2)dx\int (4x - 1) \, dx + \int \frac{-1}{(x - 2)} \, dx from x=3x = 3 to x=4x = 4.
  5. Integrate First Part: Integrate the first part of the expression.\newlineThe integral of 4x14x - 1 with respect to xx is 2x2x2x^2 - x. We will evaluate this from x=3x = 3 to x=4x = 4.
  6. Integrate Second Part: Integrate the second part of the expression.\newlineThe integral of 1x2-\frac{1}{x - 2} with respect to xx is lnx2-\ln|x - 2|. We will evaluate this from x=3x = 3 to x=4x = 4.
  7. Evaluate Definite Integrals: Evaluate the definite integrals.\newlineFirst, evaluate 2x2x2x^2 - x from x=3x = 3 to x=4x = 4:\newline(2(4)24)(2(3)23)=(2×164)(2×93)=(324)(183)=2815=13(2(4)^2 - 4) - (2(3)^2 - 3) = (2\times16 - 4) - (2\times9 - 3) = (32 - 4) - (18 - 3) = 28 - 15 = 13.\newlineNext, evaluate lnx2-\ln|x - 2| from x=3x = 3 to x=4x = 4:\newline(ln42)(ln32)=(ln2)(ln1)=ln(2)(ln(1))=ln(2)0=ln(2)(-\ln|4 - 2|) - (-\ln|3 - 2|) = (-\ln|2|) - (-\ln|1|) = -\ln(2) - (-\ln(1)) = -\ln(2) - 0 = -\ln(2).
  8. Combine Results: Combine the results.\newlineThe value of the integral is the sum of the results from steps 77 and 88:\newline13ln(2)13 - \ln(2).

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