Q. Evaluate ∫34x−52x2−15x+22dx. Write your answer in simplest form with all logs condensed into a single logarithm (if necessary).Submit Answer
Identify Integral: Identify the integral to be evaluated.We need to evaluate the integral of the function (2x2−15x+22)/(x−5) from x=3 to x=4.
Perform Long Division: Perform polynomial long division.Before integrating, we should simplify the integrand by performing polynomial long division of (2x2−15x+22) by (x−5).
Carry Out Division: Carry out the long division.Dividing 2x2 by x gives 2x. Multiply (x−5) by 2x to get 2x2−10x. Subtract this from the original polynomial to get −5x+22. Dividing −5x by x gives −5. Multiply (x−5) by −5 to get x2. Subtract this from −5x+22 to get x4. The result of the division is x5 with a remainder of x4.So, x7.
Set Up Integral: Set up the integral with the simplified integrand.Now we can write the integral as:∫34(2x−5)dx−∫34(x−53)dx.
Integrate First Part: Integrate the first part of the simplified integrand.The integral of 2x−5 with respect to x is x2−5x.
Integrate Second Part: Integrate the second part of the simplified integrand.The integral of x−53 with respect to x is 3ln∣x−5∣.
Combine and Evaluate: Combine the integrals and evaluate from 3 to 4. The combined integral is (x2−5x)−3ln∣x−5∣ from x=3 to x=4.
Evaluate Definite Integral: Evaluate the definite integral.Plug in the upper limit x=4 and the lower limit x=3 into the antiderivative and subtract the two results.For x=4: (42−5⋅4)−3ln∣4−5∣=(16−20)−3ln∣−1∣=−4−3ln(1)For x=3: (32−5⋅3)−3ln∣3−5∣=(9−15)−3ln∣−2∣=−6−3ln(2)Now subtract the lower limit result from the upper limit result: (−4−3ln(1))−(−6−3ln(2))=−4+6−3ln(1)+3ln(2)=2+3ln(2)
Simplify Final Expression: Simplify the final expression.Since ln(1) is 0, the expression simplifies to 2+3ln(2).
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