Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Emily is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 
0.375%. If Emily would like to end up with 
$4,000 after 13 months, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Emily is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 0.375% 0.375 \% . If Emily would like to end up with $4,000 \$ 4,000 after 1313 months, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Emily is saving money and plans on making monthly contributions into an account earning a monthly interest rate of 0.375% 0.375 \% . If Emily would like to end up with $4,000 \$ 4,000 after 1313 months, how much does she need to contribute to the account every month, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineAA (future value of the account) = $4,000\$4,000\newlineii (interest rate per period) = 0.375%0.375\% per month or 0.003750.00375 in decimal form\newlinenn (number of periods) = 1313 months\newlineWe need to find dd (the amount invested at the end of each period).
  2. Convert Interest Rate: Convert the interest rate from a percentage to a decimal. i=0.375%=0.375100=0.00375i = 0.375\% = \frac{0.375}{100} = 0.00375
  3. Substitute Values into Formula: Substitute the values into the formula.\newlineA=d×((1+i)n1i)A = d \times \left(\frac{(1 + i)^{n} - 1}{i}\right)\newline$4,000=d×((1+0.00375)1310.00375)\$4,000 = d \times \left(\frac{(1 + 0.00375)^{13} - 1}{0.00375}\right)
  4. Calculate Value Inside Parentheses: Calculate the value inside the parentheses.\newline(1+0.00375)131(1 + 0.00375)^{13} - 1\newline= (1.00375)131(1.00375)^{13} - 1\newline= 1.0501611.05016 - 1\newline= 0.050160.05016
  5. Divide by Interest Rate: Divide the result by the interest rate.\newline0.05016/0.003750.05016 / 0.00375\newline= 13.37613.376
  6. Solve for d: Solve for d by dividing the future value AA by the result from Step 55.\newlined=$4,00013.376d = \frac{\$4,000}{13.376}\newlined299.11d \approx 299.11
  7. Round Monthly Contribution: Round the monthly contribution to the nearest dollar. \newlined$299.11d \approx \$299.11\newlineEmily needs to contribute approximately $299\$299 per month.

More problems from Compound interest