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Does $(1,\ 1)$ make the inequality 3x + 16y > 20 true? $\newline$ Choices: $\newline$ (A)yes $\newline$ (B)no

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Does (x, y) satisfy the inequality?

Full solution

Q. Does

(1,\ 1)

make the inequality

3x + 16y > 20

true?

\newline

Choices:

\newline

(A)yes

\newline

(B)no

Substitute values into inequality: Substitute the values $(1, 1)$ into the inequality 3x + 16y > 20. The substituted inequality is 3(1) + 16(1) > 20.
Simplify left side: Simplify the left side of the inequality $3(1) + 16(1)$ to get $3 + 16$ .
Find sum: Add the numbers together to find the sum: $3 + 16 = 19$ .
Check if inequality is true: The inequality 3(1) + 16(1) > 20 becomes 19 > 20. Now, determine if the point $(1, 1)$ makes the inequality 3x + 16y > 20 true. Since $19$ is not greater than $20$ , the statement 19 > 20 is false. Therefore, the point $(1, 1)$ does not make the inequality 3x + 16y > 20 true.

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