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Divide. Write your answer in simplest form. \newlinev2v+3÷5v1v24\frac{v}{2v + 3} \div \frac{5v - 1}{v^2 - 4}

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Q. Divide. Write your answer in simplest form. \newlinev2v+3÷5v1v24\frac{v}{2v + 3} \div \frac{5v - 1}{v^2 - 4}
  1. Write Problem: Write the original problem and identify the expressions to be divided.\newlineWe have the expression v2v+3÷5v1v24\frac{v}{2v + 3} \div \frac{5v - 1}{v^2 - 4}.\newlineRewrite the division as multiplication by the reciprocal of the second fraction.\newlineThe expression becomes v2v+3×v245v1\frac{v}{2v + 3} \times \frac{v^2 - 4}{5v - 1}.
  2. Rewrite Division: Factor the denominator of the second fraction if possible.\newlineNotice that v24v^2 - 4 is a difference of squares and can be factored into (v+2)(v2)(v + 2)(v - 2).\newlineSo, the expression becomes v2v+3×(v+2)(v2)5v1.\frac{v}{2v + 3} \times \frac{(v + 2)(v - 2)}{5v - 1}.
  3. Factor Denominator: Multiply the numerators and the denominators.\newlineNow, multiply the numerators together and the denominators together.\newlineThe expression becomes (v×(v+2)(v2))/((2v+3)(5v1))(v \times (v + 2)(v - 2))/((2v + 3)(5v - 1)).
  4. Multiply Numerators: Simplify the expression if possible.\newlineLook for common factors in the numerator and the denominator that can be canceled out.\newlineIn this case, there are no common factors to cancel, so the expression is already in its simplest form.\newlineThe simplified expression is (v(v+2)(v2))/((2v+3)(5v1))(v(v + 2)(v - 2))/((2v + 3)(5v - 1)).

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