Divide. Write your answer in simplest form. 9r^2 - 1/r + 3 ÷ 2r ______

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Write as fraction: Write the division problem as a fraction. We have the expression (9r^2 - 1)/(r + 3) ÷ 2r. To simplify the division, we can rewrite it as a multiplication by the reciprocal of the second term. So, we rewrite the division as (9r^2 - 1)/(r + 3) * 1/(2r).Factor numerator: Factor the numerator of the first fraction if possible. The numerator 9r^2 - 1 is a difference of squares and can be factored into (3r + 1)(3r - 1). The factored form of the first fraction is ((3r + 1)(3r - 1))/(r + 3).Multiply by reciprocal: Multiply the first fraction by the reciprocal of the second term. Now we multiply ((3r + 1)(3r - 1))/(r + 3) by 1/(2r). The expression becomes ((3r + 1)(3r - 1))/(r + 3) * 1/(2r).Multiply numerators and denominators: Multiply the numerators and the denominators. When we multiply fractions, we multiply the numerators together and the denominators together. The expression becomes ((3r + 1)(3r - 1))/(2r(r + 3)).Simplify expression: Simplify the expression if possible. We look for common factors in the numerator and the denominator that can be canceled out. However, there are no common factors between (3r + 1)(3r - 1) and 2r(r + 3), so the expression is already in its simplest form.

Divide. Write your answer in simplest form. $\newline$ $\frac{9r^2 - 1}{r + 3} \div 2r$

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Divide. Write your answer in simplest form. \newline9r2−1r+3÷2r\frac{9r^2 - 1}{r + 3} \div 2rr+39r2−1​÷2r

Divide. Write your answer in simplest form. $\newline$ $\frac{9r^2 - 1}{r + 3} \div 2r$