Divide. Write your answer in simplest form. 5/2g ÷ (2g - 3) ______

Rewrite Division as Multiplication: Rewrite the division as a multiplication by taking the reciprocal of the divisor. So, 5/2g ÷ (2g - 3) becomes 5/2g × 1/(2g - 3).Multiply Numerators and Denominators: Multiply the numerators and then multiply the denominators. So, 5/2g × 1/(2g - 3) becomes (5 × 1) / (2g × (2g - 3)).Simplify Numerator and Expand Denominator: Simplify the numerator and expand the denominator. The numerator is simply 5, and the denominator is 2g(2g) - 2g(3), which simplifies to 4g^2 - 6g.Write Final Answer: Write the answer in the simplest form. So, the final answer is 5 / (4g^2 - 6g).

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Divide. Write your answer in simplest form. $\newline$ $\frac{5}{2g} \div (2g - 3)$

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Algebra 1

Multiply and divide rational expressions

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Q. Divide. Write your answer in simplest form.

\newline

\frac{5}{2g} \div (2g - 3)

Rewrite Division as Multiplication: Rewrite the division as a multiplication by taking the reciprocal of the divisor. So, $\frac{5}{2g} \div (2g - 3)$ becomes $\frac{5}{2g} \times \frac{1}{(2g - 3)}$ .
Multiply Numerators and Denominators: Multiply the numerators and then multiply the denominators. So, $\frac{5}{2g} \times \frac{1}{(2g - 3)}$ becomes $\frac{(5 \times 1)}{(2g \times (2g - 3))}$ .
Simplify Numerator and Expand Denominator: Simplify the numerator and expand the denominator. The numerator is simply $5$ , and the denominator is $2g(2g) - 2g(3)$ , which simplifies to $4g^2 - 6g$ .
Write Final Answer: Write the answer in the simplest form. So, the final answer is $\frac{5}{4g^2 - 6g}$ .