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Divide. Write your answer in simplest form.\newline2j35j+1÷(4j1)\frac{2j - 3}{5j + 1} \div (4j - 1)

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Q. Divide. Write your answer in simplest form.\newline2j35j+1÷(4j1)\frac{2j - 3}{5j + 1} \div (4j - 1)
  1. Rewrite as multiplication: Rewrite the division as a multiplication by taking the reciprocal of the divisor. So, (2j3)/(5j+1)÷(4j1)(2j - 3)/(5j + 1) \div (4j - 1) becomes (2j3)/(5j+1)×1/(4j1)(2j - 3)/(5j + 1) \times 1/(4j - 1).
  2. Multiply numerators and denominators: Multiply the numerators and then multiply the denominators. So, (2j3)/(5j+1)×1/(4j1)(2j - 3)/(5j + 1) \times 1/(4j - 1) becomes (2j3)/((5j+1)(4j1))(2j - 3) / ((5j + 1)(4j - 1)).
  3. Simplify denominator: Simplify the denominator by multiplying the two binomials. So, (5j+1)(4j1)=20j24j+5j1(5j + 1)(4j - 1) = 20j^2 - 4j + 5j - 1.
  4. Combine like terms: Combine like terms in the denominator. So, 20j24j+5j120j^2 - 4j + 5j - 1 becomes 20j2+j120j^2 + j - 1.
  5. Write in simplest form: Write the answer in the simplest form. So, (2j3)/((5j+1)(4j1))(2j - 3) / ((5j + 1)(4j - 1)) becomes (2j3)/(20j2+j1)(2j - 3) / (20j^2 + j - 1).

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