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Divide. Write your answer in simplest form. \newline14g7g+1÷3g+53g\frac{14g - 7}{g + 1} \div \frac{3g + 5}{3g}

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Q. Divide. Write your answer in simplest form. \newline14g7g+1÷3g+53g\frac{14g - 7}{g + 1} \div \frac{3g + 5}{3g}
  1. Identify Common Factors: Now, we look for common factors in the numerators and denominators that can be simplified. The numerator 14g714g - 7 can be factored as 7(2g1)7(2g - 1) because 14g=7×2g14g = 7 \times 2g and 7=7×1-7 = 7 \times -1. The expression becomes (7(2g1))/(g+1)×(3g)/(3g+5)(7(2g - 1))/(g + 1) \times (3g)/(3g + 5).
  2. Multiply Numerators and Denominators: Next, we multiply the numerators together and the denominators together.\newlineMultiplying the numerators: 7(2g1)×3g=21g(2g1)7(2g - 1) \times 3g = 21g(2g - 1).\newlineMultiplying the denominators: (g+1)(3g+5)(g + 1)(3g + 5).\newlineThe expression now looks like this: 21g(2g1)(g+1)(3g+5)\frac{21g(2g - 1)}{(g + 1)(3g + 5)}.
  3. Check for Common Factors: We should check if there are any common factors between the numerator and the denominator that can be canceled out.\newlineHowever, there are no common factors between 21g(2g1)21g(2g - 1) and (g+1)(3g+5)(g + 1)(3g + 5), so the expression is already in its simplest form.
  4. Final Answer: The final answer is the expression we have after the multiplication, which is (21g(2g1))/((g+1)(3g+5))(21g(2g - 1))/((g + 1)(3g + 5)).

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