Divide the polynomials. Your answer should be a polynomial. (x^(2)-3x-10)/(x-5)=

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Divide the polynomials. Your answer should be a polynomial.  (x^(2)-3x-10)/(x-5)=

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Set up division format: Set up the division of the polynomials in long division format. We want to divide $x^2 - 3x - 10$ by $x - 5$. This is similar to long division with numbers.Divide first terms: Divide the first term of the dividend, $x^2$, by the first term of the divisor, $x$, to get the first term of the quotient. $x^2 \div x = x$. Write $x$ above the division bar.Multiply and subtract: Multiply the divisor $x - 5$ by the first term of the quotient $x$ and write the result under the dividend. $x \times (x - 5) = x^2 - 5x$.Simplify and divide again: Subtract the result of the multiplication from the dividend. $(x^2 - 3x - 10) - (x^2 - 5x) = x^2 - 3x - 10 - x^2 + 5x$.Multiply and subtract again: Simplify the subtraction to find the new dividend. $x^2 - 3x - 10 - x^2 + 5x = 2x - 10$.Simplify and find remainder: Divide the new dividend $2x - 10$ by the first term of the divisor $x$ to find the next term of the quotient. $2x \div x = 2$. Write $2$ above the division bar next to the first term of the quotient.Multiply the divisor $x - 5$ by the new term of the quotient $2$ and write the result under the new dividend. $2 \times (x - 5) = 2x - 10$.Subtract the result of the multiplication from the new dividend. $(2x - 10) - (2x - 10) = 2x - 10 - 2x + 10$.Simplify the subtraction to find the remainder. $2x - 10 - 2x + 10 = 0$. The remainder is 0, so the division is exact.

Divide the polynomials. Your answer should be a polynomial. $\newline$ $\frac{x^{2}-3 x-10}{x-5}=$

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Divide the polynomials. Your answer should be a polynomial.\newlinex2−3x−10x−5= \frac{x^{2}-3 x-10}{x-5}= x−5x2−3x−10​=

Divide the polynomials. Your answer should be a polynomial. $\newline$ $\frac{x^{2}-3 x-10}{x-5}=$