Divide the polynomials. Your answer should be a polynomial. (x^(2)+x-6)/(x+3)=

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Divide the polynomials. Your answer should be a polynomial.  (x^(2)+x-6)/(x+3)=

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Set up division format: Set up the division of the polynomials in long division format. We want to divide $x^2 + x - 6$ by $x + 3$. We will use polynomial long division to find the quotient.Divide first term: Divide the first term of the dividend, $x^2$, by the first term of the divisor, $x$, to get the first term of the quotient. $x^2$ divided by $x$ is $x$. Write $x$ above the division bar.Multiply and subtract: Multiply the divisor $x + 3$ by the first term of the quotient $x$ and write the result under the dividend. $x \times (x + 3) = x^2 + 3x$. Write this under $x^2 + x$.Bring down next term: Subtract the result from the previous step from the dividend. Subtract $x^2 + 3x$ from $x^2 + x$. This gives us $-2x - 6$.Divide new dividend: Bring down the next term of the dividend, which is $-6$, to complete the new dividend of $-2x - 6$. Now we have a new dividend of $-2x - 6$.Multiply and subtract again: Divide the first term of the new dividend, $-2x$, by the first term of the divisor, $x$, to get the next term of the quotient. $-2x$ divided by $x$ is $-2$. Write $-2$ above the division bar next to $x$.Subtract and find remainder: Multiply the divisor $x + 3$ by the new term of the quotient $-2$ and write the result under the new dividend. $-2 \times (x + 3) = -2x - 6$. Write this under $-2x - 6$.Write final answer: Subtract the result from the previous step from the new dividend. Subtract $-2x - 6$ from $-2x - 6$. This gives us a remainder of $0$.Write the final answer. The quotient is $x - 2$ with a remainder of $0$, so the final answer is $x - 2$.

Divide the polynomials. Your answer should be a polynomial. $\newline$ $\frac{x^{2}+x-6}{x+3}=$

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Divide the polynomials. Your answer should be a polynomial. $\newline$ $\frac{x^{2}+x-6}{x+3}=$