Divide the polynomials. Your answer should be a polynomial. (x^(2)+2x-3)/(x-1)=

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Divide the polynomials. Your answer should be a polynomial.  (x^(2)+2x-3)/(x-1)=

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Set up long division: Set up the long division. We will divide $x^2 + 2x - 3$ by $x - 1$. This is similar to long division with numbers, but with polynomials.Divide first term of dividend: Divide the first term of the dividend by the first term of the divisor. Divide $x^2$ by $x$ to get $x$. This will be the first term of the quotient.Multiply divisor by first term of quotient: Multiply the divisor by the first term of the quotient. Multiply $x - 1$ by $x$ to get $x^2 - x$.Subtract result from dividend: Subtract the result from the dividend. Subtract $x^2 - x$ from $x^2 + 2x - 3$ to get $3x - 3$.Bring down next term of dividend: Bring down the next term of the dividend. There are no more terms to bring down, so we continue with $3x - 3$.Divide first term of new dividend: Divide the first term of the new dividend by the first term of the divisor. Divide $3x$ by $x$ to get $3$. This will be the next term of the quotient.Multiply divisor by new term of quotient: Multiply the divisor by the new term of the quotient. Multiply $x - 1$ by $3$ to get $3x - 3$.Subtract result from new dividend: Subtract the result from the new dividend. Subtract $3x - 3$ from $3x - 3$ to get $0$.Find the quotient: Since the remainder is $0$, we have found the quotient. The quotient is $x + 3$.

Divide the polynomials. $\newline$ Your answer should be a polynomial. $\newline$ $\frac{x^{2}+2 x-3}{x-1}=$

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Divide the polynomials. $\newline$ Your answer should be a polynomial. $\newline$ $\frac{x^{2}+2 x-3}{x-1}=$