Divide the polynomials. Your answer should be a polynomial. (x^(2)-2x+1)/(x-1)=

Recognize Approach: Recognize that the division (x^2 - 2x + 1) / (x - 1) can be approached by polynomial long division or by factoring and simplifying if possible.Factor Perfect Square Trinomial: Notice that the numerator x^2 - 2x + 1 is a perfect square trinomial, which factors into (x - 1)^2.Rewrite Division: Rewrite the division as (x - 1)^2 / (x - 1).Simplify Expression: Simplify the expression by canceling out one (x - 1) from the numerator and the denominator, which leaves us with x - 1.Check Result: Check the result by multiplying the quotient (x - 1) by the divisor (x - 1) to see if we get the original dividend (x^2 - 2x + 1). (x - 1) * (x - 1) = x^2 - 2x + 1

Home

Math Problems

Algebra 2

Factor sums and differences of cubes

Full solution

Q. Divide the polynomials.

\newline

Your answer should be a polynomial.

\newline

\frac{x^{2}-2 x+1}{x-1}=

Recognize Approach: Recognize that the division $(x^2 - 2x + 1) / (x - 1)$ can be approached by polynomial long division or by factoring and simplifying if possible.
Factor Perfect Square Trinomial: Notice that the numerator $x^2 - 2x + 1$ is a perfect square trinomial, which factors into $(x - 1)^2$ .
Rewrite Division: Rewrite the division as $(x - 1)^2 / (x - 1)$ .
Simplify Expression: Simplify the expression by canceling out one $x - 1$ from the numerator and the denominator, which leaves us with $x - 1$ .
Check Result: Check the result by multiplying the quotient $(x - 1)$ by the divisor $(x - 1)$ to see if we get the original dividend $x^2 - 2x + 1$ . $(x - 1) \times (x - 1) = x^2 - 2x + 1$