Divide the polynomials. Your answer should be a polynomial. (x^(2)-9)/(x-3)=

Recognizing the difference of squares: We recognize that the numerator x^2 - 9 is a difference of squares, which can be factored into (x + 3)(x - 3). So, we rewrite the expression as: (x^2 - 9) / (x - 3) = [(x + 3)(x - 3)] / (x - 3)Canceling out the common factor: Next, we can cancel out the common factor (x - 3) in the numerator and the denominator, which gives us: [(x + 3)(x - 3)] / (x - 3) = x + 3Final result: After canceling out the common factor, we are left with the polynomial x + 3, which is the result of the division.

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Divide the polynomials.
Your answer should be a polynomial.

(x^(2)-9)/(x-3)=

Divide the polynomials. $\newline$ Your answer should be a polynomial. $\newline$ $\frac{x^{2}-9}{x-3}=$

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Algebra 2

Factor sums and differences of cubes

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Q. Divide the polynomials.

\newline

Your answer should be a polynomial.

\newline

\frac{x^{2}-9}{x-3}=

Recognizing the difference of squares: We recognize that the numerator $x^2 - 9$ is a difference of squares, which can be factored into $(x + 3)(x - 3)$ . So, we rewrite the expression as: $(x^2 - 9) / (x - 3) = [(x + 3)(x - 3)] / (x - 3)$
Canceling out the common factor: Next, we can cancel out the common factor $(x - 3)$ in the numerator and the denominator, which gives us: $\newline$ $\frac{(x + 3)(x - 3)}{x - 3} = x + 3$
Final result: After canceling out the common factor, we are left with the polynomial $x + 3$ , which is the result of the division.