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Divide. Simplify your answer.\newline7gh19h2÷15g21\frac{7gh}{19h^2} \div \frac{15g^2}{1}

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Q. Divide. Simplify your answer.\newline7gh19h2÷15g21\frac{7gh}{19h^2} \div \frac{15g^2}{1}
  1. Rewrite as multiplication: Rewrite the division as a multiplication by taking the reciprocal of the second fraction. So, (7gh19h2)÷(15g2)(\frac{7gh}{19h^2}) \div (15g^2) becomes (7gh19h2)×(115g2)(\frac{7gh}{19h^2}) \times (\frac{1}{15g^2}).
  2. Multiply numerators and denominators: Multiply the numerators and then multiply the denominators. So, (7gh19h2)×(115g2)=7gh×119h2×15g2(\frac{7gh}{19h^2}) \times (\frac{1}{15g^2}) = \frac{7gh \times 1}{19h^2 \times 15g^2}.
  3. Cancel out common factors: Simplify the expression by canceling out common factors. The gg in the numerator and one gg in the denominator cancel out, leaving us with (7h×1)/(19h2×15g)(7h \times 1)/(19h^2 \times 15g). Similarly, hh in the numerator and one hh in the denominator cancel out, giving us (7×1)/(19h×15g)(7 \times 1)/(19h \times 15g).
  4. Simplify further: Simplify the fraction further by multiplying the denominators. So, (7×1)/(19h×15g)=7/(19×15gh)(7 \times 1)/(19h \times 15g) = 7/(19 \times 15gh).
  5. Multiply denominators: Multiply the numbers in the denominator to get the final simplified form. So, 719×15gh=7285gh.\frac{7}{19 \times 15gh} = \frac{7}{285gh}.
  6. Check for simplification: Check for any further simplification. Since there are no common factors between 77 and 285gh285gh, the fraction is already in its simplest form.

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