Divide. Simplify your answer. 6p^2/19pq^2 ÷ 18p^2 ______

Rewrite as multiplication: Rewrite the division as a multiplication by taking the reciprocal of the second fraction. So, (6p^2/19pq^2) ÷ (18p^2) becomes (6p^2/19pq^2) × (1/18p^2).Multiply numerators and denominators: Multiply the numerators and then multiply the denominators. So, (6p^2/19pq^2) × (1/18p^2) becomes (6p^2 × 1)/(19pq^2 × 18p^2).Simplify by canceling common factors: Simplify the expression by canceling out common factors. The p^2 in the numerator cancels with one p^2 in the denominator. The result is (6 × 1)/(19q^2 × 18).Multiply constants in denominator: Multiply the constants in the denominator. So, 19q^2 × 18 becomes 342q^2.Write in simplest form: Write the answer in the simplest form. So, (6 × 1)/(342q^2) simplifies to 1/(57q^2) after dividing both numerator and denominator by 6.

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Divide. Simplify your answer. $\newline$ $\frac{6p^2}{19pq^2} \div 18p^2$

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Algebra 1

Multiply and divide rational expressions

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Q. Divide. Simplify your answer.

\newline

\frac{6p^2}{19pq^2} \div 18p^2

Rewrite as multiplication: Rewrite the division as a multiplication by taking the reciprocal of the second fraction. So, $(\frac{6p^2}{19pq^2}) \div (18p^2)$ becomes $(\frac{6p^2}{19pq^2}) \times (\frac{1}{18p^2})$ .
Multiply numerators and denominators: Multiply the numerators and then multiply the denominators. So, $(\frac{6p^2}{19pq^2}) \times (\frac{1}{18p^2})$ becomes $(\frac{6p^2 \times 1}{19pq^2 \times 18p^2})$ .
Simplify by canceling common factors: Simplify the expression by canceling out common factors. The $p^2$ in the numerator cancels with one $p^2$ in the denominator. The result is $(6 \times 1)/(19q^2 \times 18)$ .
Multiply constants in denominator: Multiply the constants in the denominator. So, $19q^2 \times 18$ becomes $342q^2$ .
Write in simplest form: Write the answer in the simplest form. So, $(6 \times 1)/(342q^2)$ simplifies to $1/(57q^2)$ after dividing both numerator and denominator by $6$ .