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Divide. Simplify your answer. \newline17u2v18u2v2÷7v\frac{17u^2v}{18u^2v^2} \div 7v

Full solution

Q. Divide. Simplify your answer. \newline17u2v18u2v2÷7v\frac{17u^2v}{18u^2v^2} \div 7v
  1. Rewrite as multiplication: Rewrite the division as a multiplication by taking the reciprocal of the divisor. So, (17u2v/18u2v2)÷7v=(17u2v/18u2v2)×(1/7v)(17u^2v/18u^2v^2) \div 7v = (17u^2v/18u^2v^2) \times (1/7v).
  2. Multiply numerators and denominators: Multiply the numerators and then multiply the denominators. So, (17u2v18u2v2)×(17v)=17u2v×118u2v2×7v(\frac{17u^2v}{18u^2v^2}) \times (\frac{1}{7v}) = \frac{17u^2v \times 1}{18u^2v^2 \times 7v}.
  3. Simplify by canceling common factors: Simplify the expression by canceling out common factors. u2u^2 cancels out, and vv cancels out once because v2v^2 is vvv*v. So, (17u2v×1)/(18u2v2×7v)=(17)/(18v×7)(17u^2v \times 1)/(18u^2v^2 \times 7v) = (17)/(18v \times 7).
  4. Multiply denominators: Multiply the denominators. So, 18v×7=126v18v \times 7 = 126v.
  5. Write in simplest form: Write the answer in the simplest form. So, (17)/(18v×7)=17/126v(17)/(18v \times 7) = 17/126v.

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