Divide. Simplify your answer. 13x^2/16x^2y^2 ÷ 18xy ______

Rewrite as multiplication: Rewrite the division as a multiplication by taking the reciprocal of the second fraction. So, (13x^2/16x^2y^2) ÷ (18xy) becomes (13x^2/16x^2y^2) × (1/18xy).Multiply numerators and denominators: Multiply the numerators and then multiply the denominators. So, (13x^2/16x^2y^2) × (1/18xy) = (13x^2 × 1) / (16x^2y^2 × 18xy).Simplify by canceling common factors: Simplify the expression by canceling out common factors. The x^2 term in the numerator cancels with one x^2 in the denominator, and the x in the denominator cancels with one x in the numerator. This leaves us with 13 / (16y^2 × 18y).Further simplify the denominator: Further simplify the denominator by multiplying the constants and the y terms. So, 16y^2 × 18y = 288y^3.Write in simplest form: Write the answer in the simplest form. So, 13 / (16y^2 × 18y) = 13 / 288y^3.

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Divide. Simplify your answer. $\newline$ $\frac{13x^2}{16x^2y^2} \div 18xy$

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Algebra 1

Multiply and divide rational expressions

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Q. Divide. Simplify your answer.

\newline

\frac{13x^2}{16x^2y^2} \div 18xy

Rewrite as multiplication: Rewrite the division as a multiplication by taking the reciprocal of the second fraction. So, $(\frac{13x^2}{16x^2y^2}) \div (18xy)$ becomes $(\frac{13x^2}{16x^2y^2}) \times (\frac{1}{18xy})$ .
Multiply numerators and denominators: Multiply the numerators and then multiply the denominators. So, $(\frac{13x^2}{16x^2y^2}) \times (\frac{1}{18xy}) = \frac{13x^2 \times 1}{16x^2y^2 \times 18xy}$ .
Simplify by canceling common factors: Simplify the expression by canceling out common factors. The $x^2$ term in the numerator cancels with one $x^2$ in the denominator, and the $x$ in the denominator cancels with one $x$ in the numerator. This leaves us with $\frac{13}{(16y^2 \times 18y)}$ .
Further simplify the denominator: Further simplify the denominator by multiplying the constants and the $y$ terms. So, $16y^2 \times 18y = 288y^3$ .
Write in simplest form: Write the answer in the simplest form. So, $\frac{13}{16y^2 \times 18y} = \frac{13}{288y^3}$ .