Divide. Simplify your answer. 12q^2/9pq^2 ÷ 13p^2 ______

Rewrite as multiplication: Rewrite the division as a multiplication by taking the reciprocal of the second fraction. So, (12q^2/9pq^2) ÷ (13p^2) becomes (12q^2/9pq^2) × (1/13p^2).Multiply numerators and denominators: Multiply the numerators and then multiply the denominators. So, (12q^2/9pq^2) × (1/13p^2) becomes (12q^2 × 1)/(9pq^2 × 13p^2).Simplify by canceling common factors: Simplify the expression by canceling out common factors. The q^2 terms cancel out, and 12 can be divided by 9 to get 4/3. So, (12q^2 × 1)/(9pq^2 × 13p^2) simplifies to (4/3) × (1/13p^3).Multiply numerators and denominators: Multiply the numerators and denominators. So, (4/3) × (1/13p^3) becomes 4/(3 × 13p^3).Simplify the denominator: Simplify the denominator by multiplying 3 and 13. So, 4/(3 × 13p^3) becomes 4/(39p^3).

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Algebra 1

Multiply and divide rational expressions

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Q. Divide. Simplify your answer.

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\frac{12q^2}{9pq^2} \div 13p^2

Rewrite as multiplication: Rewrite the division as a multiplication by taking the reciprocal of the second fraction. So, $(\frac{12q^2}{9pq^2}) \div (13p^2)$ becomes $(\frac{12q^2}{9pq^2}) \times (\frac{1}{13p^2})$ .
Multiply numerators and denominators: Multiply the numerators and then multiply the denominators. So, $(\frac{12q^2}{9pq^2}) \times (\frac{1}{13p^2})$ becomes $(\frac{12q^2 \times 1}{9pq^2 \times 13p^2})$ .
Simplify by canceling common factors: Simplify the expression by canceling out common factors. The $q^2$ terms cancel out, and $12$ can be divided by $9$ to get $\frac{4}{3}$ . So, $(12q^2 \times 1)/(9pq^2 \times 13p^2)$ simplifies to $(\frac{4}{3}) \times (\frac{1}{13p^3})$ .
Multiply numerators and denominators: Multiply the numerators and denominators. So, $(\frac{4}{3}) \times (\frac{1}{13p^3})$ becomes $\frac{4}{3 \times 13p^3}$ .
Simplify the denominator: Simplify the denominator by multiplying $3$ and $13$ . So, $\frac{4}{3 \times 13p^3}$ becomes $\frac{4}{39p^3}$ .