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Let’s check out your problem:
Divide.
\newline
27
64
3
\sqrt[3]{\frac{27}{64}}
3
64
27
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Math Problems
Algebra 2
Roots of rational numbers
Full solution
Q.
Divide.
\newline
27
64
3
\sqrt[3]{\frac{27}{64}}
3
64
27
Calculate Cube Root Separately:
Calculate the cube root of the numerator and the denominator separately.
27
64
3
=
27
3
64
3
\sqrt[3]{\frac{27}{64}} = \frac{\sqrt[3]{27}}{\sqrt[3]{64}}
3
64
27
=
3
64
3
27
Find Cube Roots:
Find the cube root of
27
27
27
and
64
64
64
.
27
3
=
3
\sqrt[3]{27} = 3
3
27
=
3
because
3
3
=
27
3^3 = 27
3
3
=
27
64
3
=
4
\sqrt[3]{64} = 4
3
64
=
4
because
4
3
=
64
4^3 = 64
4
3
=
64
Divide Results:
Divide the results of the cube roots.
27
64
3
=
3
4
\sqrt[3]{\frac{27}{64}} = \frac{3}{4}
3
64
27
=
4
3
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\underline{\hspace{3cm}}
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What is the value of
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sin
(
6
5
π
)
?
\newline
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1
1
1
answer:
\newline
(A)
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−
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