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Distribute to create an equivalent expression with the fewest symbols possible.
(
1
−
2
g
+
4
h
)
⋅
5
=
( 1 -2g +4h)\cdot 5 =
(
1
−
2
g
+
4
h
)
⋅
5
=
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Math Problems
Algebra 2
Csc, sec, and cot of special angles
Full solution
Q.
Distribute to create an equivalent expression with the fewest symbols possible.
(
1
−
2
g
+
4
h
)
⋅
5
=
( 1 -2g +4h)\cdot 5 =
(
1
−
2
g
+
4
h
)
⋅
5
=
Distribute and Multiply:
To distribute the number
5
5
5
to each term inside the parentheses, we multiply each term by
5
5
5
.
\newline
(
1
−
2
g
+
4
h
)
×
5
=
5
×
1
−
5
×
2
g
+
5
×
4
h
(1 - 2g + 4h) \times 5 = 5 \times 1 - 5 \times 2g + 5 \times 4h
(
1
−
2
g
+
4
h
)
×
5
=
5
×
1
−
5
×
2
g
+
5
×
4
h
Perform Multiplication:
Now we perform the multiplication for each term.
\newline
5
×
1
=
5
5 \times 1 = 5
5
×
1
=
5
\newline
5
×
2
g
=
10
g
5 \times 2g = 10g
5
×
2
g
=
10
g
\newline
5
×
4
h
=
20
h
5 \times 4h = 20h
5
×
4
h
=
20
h
Combine Results:
Combine the results to get the final expression.
5
−
10
g
+
20
h
5 - 10g + 20h
5
−
10
g
+
20
h
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