Apply Chain Rule: Apply the chain rule to differentiate the function y=(10x−65x+3)4. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
Find dudy: Let u=10x−65x+3. Then y=u4. We will first find the derivative of y with respect to u, which is dudy=4u3.
Find dxdu: Now we need to find the derivative of u with respect to x, dxdu. To do this, we will use the quotient rule, which states that the derivative of a quotient is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all over the square of the denominator.
Apply Quotient Rule: Differentiate the numerator 5x+3 and the denominator 10x−6 separately. The derivative of the numerator with respect to x is dxd(5x+3)=5, and the derivative of the denominator with respect to x is dxd(10x−6)=10.
Simplify dxdu: Apply the quotient rule: dxdu=(10x−6)2(10x−6)⋅5−(5x+3)⋅10.
Find dxdy: Simplify the expression in the numerator: dxdu=(10x−6)2(50x−30−50x−30)=(10x−6)2−60.
Substitute u: Now we have dxdu and dudy, so we can find dxdy by multiplying these two derivatives: dxdy=dudy×dxdu=4u3×(−(10x−6)260).
Simplify dxdy: Substitute u back into the equation to get dxdy in terms of x: \frac{dy}{dx} = \(4\left(\frac{5x+3}{10x−6}\right)^3 \cdot \left(-\frac{60}{(10x−6)^2}\right).
Simplify dxdy: Substitute u back into the equation to get dxdy in terms of x: dxdy=4(10x−65x+3)3×(−(10x−6)260).Simplify the expression by combining the powers of (10x−6): dxdy=4×(−60)×(5x+3)3/(10x−6)5=−240×(5x+3)3/(10x−6)5.
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