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Differentiate y=(5x+310x6)4y=(\frac{5x+3}{10x-6})^4

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Q. Differentiate y=(5x+310x6)4y=(\frac{5x+3}{10x-6})^4
  1. Apply Chain Rule: Apply the chain rule to differentiate the function y=(5x+310x6)4y=(\frac{5x+3}{10x-6})^4. The chain rule states that the derivative of a composite function is the derivative of the outer function evaluated at the inner function times the derivative of the inner function.
  2. Find dydu\frac{dy}{du}: Let u=5x+310x6u = \frac{5x+3}{10x-6}. Then y=u4y = u^4. We will first find the derivative of yy with respect to uu, which is dydu=4u3\frac{dy}{du} = 4u^3.
  3. Find dudx\frac{du}{dx}: Now we need to find the derivative of uu with respect to xx, dudx\frac{du}{dx}. To do this, we will use the quotient rule, which states that the derivative of a quotient is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all over the square of the denominator.
  4. Apply Quotient Rule: Differentiate the numerator 5x+35x+3 and the denominator 10x610x-6 separately. The derivative of the numerator with respect to xx is ddx(5x+3)=5\frac{d}{dx}(5x+3) = 5, and the derivative of the denominator with respect to xx is ddx(10x6)=10\frac{d}{dx}(10x-6) = 10.
  5. Simplify dudx\frac{du}{dx}: Apply the quotient rule: dudx=(10x6)5(5x+3)10(10x6)2\frac{du}{dx} = \frac{(10x-6)\cdot 5 - (5x+3)\cdot 10}{(10x-6)^2}.
  6. Find dydx\frac{dy}{dx}: Simplify the expression in the numerator: dudx=(50x3050x30)(10x6)2=60(10x6)2\frac{du}{dx} = \frac{(50x - 30 - 50x - 30)}{(10x-6)^2} = \frac{-60}{(10x-6)^2}.
  7. Substitute uu: Now we have dudx\frac{du}{dx} and dydu\frac{dy}{du}, so we can find dydx\frac{dy}{dx} by multiplying these two derivatives: dydx=dydu×dudx=4u3×(60(10x6)2)\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx} = 4u^3 \times \left(-\frac{60}{(10x-6)^2}\right).
  8. Simplify dydx\frac{dy}{dx}: Substitute uu back into the equation to get dydx\frac{dy}{dx} in terms of xx: \frac{dy}{dx} = \(4\left(\frac{55x+33}{1010x6-6}\right)^33 \cdot \left(-\frac{6060}{(1010x6-6)^22}\right).
  9. Simplify dydx\frac{dy}{dx}: Substitute uu back into the equation to get dydx\frac{dy}{dx} in terms of xx: dydx=4(5x+310x6)3×(60(10x6)2)\frac{dy}{dx} = 4\left(\frac{5x+3}{10x-6}\right)^3 \times \left(-\frac{60}{(10x-6)^2}\right).Simplify the expression by combining the powers of (10x6)(10x-6): dydx=4×(60)×(5x+3)3/(10x6)5=240×(5x+3)3/(10x6)5\frac{dy}{dx} = 4 \times (-60) \times (5x+3)^3 / (10x-6)^5 = -240 \times (5x+3)^3 / (10x-6)^5.

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