Determine the y-intercept of the following equation. (x-5)(x+4)=y (5,0) and (-4,0) (-20,0) (0,5) and (0,-4) (0,-20) (-5,0) and (-4,0) (0,20)

Find y-intercept: We need to find the y-intercept of the equation, which is the point where the graph of the equation crosses the y-axis. This occurs when x=0.Substitute x=0: Substitute x=0 into the equation to find the y-intercept. y = (0-5)(0+4)Perform multiplication: Perform the multiplication to find the value of y. y = (-5)(4) y = -20Identify y-intercept point: The y-intercept of the equation is the point (0, y). Since we found y to be -20, the y-intercept is (0, -20).

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Determine the
y-intercept of the following equation.

(x-5)(x+4)=y

(5,0) and
(-4,0)

(-20,0)

(0,5) and
(0,-4)

(0,-20)

(-5,0) and
(-4,0)

(0,20)

Determine the $y$ -intercept of the following equation. $\newline$ $(x-5)(x+4)=y$ $\newline$ $(5,0)$ and $(-4,0)$ $\newline$ $(-20,0)$ $\newline$ $(0,5)$ and $(0,-4)$ $\newline$ $(0,-20)$ $\newline$ $(-5,0)$ and $(-4,0)$ $\newline$ $(0,20)$

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Math Problems

Algebra 2

Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

y

-intercept of the following equation.

\newline

(x-5)(x+4)=y

\newline

(5,0)

and

(-4,0)

\newline

(-20,0)

\newline

(0,5)

and

(0,-4)

\newline

(0,-20)

\newline

(-5,0)

and

(-4,0)

\newline

(0,20)

Find y-intercept: We need to find the y-intercept of the equation, which is the point where the graph of the equation crosses the y-axis. This occurs when $x=0$ .
Substitute $x=0$ : Substitute $x=0$ into the equation to find the y-intercept. $y = (0-5)(0+4)$
Perform multiplication: Perform the multiplication to find the value of $y$ . $y = (-5)(4)$ $y = -20$
Identify y-intercept point: The y-intercept of the equation is the point $(0, y)$ . Since we found $y$ to be $-20$ , the y-intercept is $(0, -20)$ .