Determine the y-intercept of the following equation. (-x+4)(x+3)=y (0,12) (0,4) and (0,-3) (0,-12) (12,0) (4,0) and (-3,0) (-4,0) and (-3,0)

Identify y-intercept: Identify the y-intercept from the equation. The y-intercept occurs when x=0. To find the y-intercept, we substitute x=0 into the equation and solve for y. (-x+4)(x+3)=y (-0+4)(0+3)=yPerform substitution and calculate: Perform the substitution and calculate the value of y. (4)(3)=y y=12Write y-intercept coordinates: Write the coordinates of the y-intercept. The y-intercept is the point where the graph of the equation crosses the y-axis. Since we have found y to be 12 when x is 0, the coordinates of the y-intercept are (0,12).

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Determine the
y-intercept of the following equation.

(-x+4)(x+3)=y

(0,12)

(0,4) and
(0,-3)

(0,-12)

(12,0)

(4,0) and
(-3,0)

(-4,0) and
(-3,0)

Determine the $y$ -intercept of the following equation. $\newline$ $(-x+4)(x+3)=y$ $\newline$ $(0,12)$ $\newline$ $(0,4)$ and $(0,-3)$ $\newline$ $(0,-12)$ $\newline$ $(12,0)$ $\newline$ $(4,0)$ and $(-3,0)$ $\newline$ $(-4,0)$ and $(-3,0)$

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Math Problems

Algebra 2

Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

y

-intercept of the following equation.

\newline

(-x+4)(x+3)=y

\newline

(0,12)

\newline

(0,4)

and

(0,-3)

\newline

(0,-12)

\newline

(12,0)

\newline

(4,0)

and

(-3,0)

\newline

(-4,0)

and

(-3,0)

Identify y-intercept: Identify the y-intercept from the equation. $\newline$ The y-intercept occurs when $x=0$ . To find the y-intercept, we substitute $x=0$ into the equation and solve for $y$ . $\newline$ $(-x+4)(x+3)=y$ $\newline$ $(-0+4)(0+3)=y$
Perform substitution and calculate: Perform the substitution and calculate the value of $y$ . $(4)(3)=y$ $y=12$
Write y-intercept coordinates: Write the coordinates of the y-intercept. $\newline$ The y-intercept is the point where the graph of the equation crosses the y-axis. Since we have found $y$ to be $12$ when $x$ is $0$ , the coordinates of the y-intercept are $(0,12)$ .