Determine the y-intercept of the following equation. (x-4)(x+2)=y (-8,0) (0,8) (0,-8) (-4,0) and (-2,0) (4,0) and (-2,0) (0,4) and (0,-2)

Find y-intercept: We need to find the y-intercept of the equation (x-4)(x+2)=y. The y-intercept occurs where x=0. Let's substitute x=0 into the equation to find the y-value of the y-intercept.Substitute x=0: Substitute x=0 into the equation: (0-4)(0+2)=y.Calculate y: Calculate the value of y: (-4)(2)=y.Perform multiplication: Perform the multiplication: y = -8.Identify y-intercept point: The y-intercept of the equation is the point where the graph crosses the y-axis, which is when x=0. Therefore, the y-intercept is (0, -8).

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Determine the
y-intercept of the following equation.

(x-4)(x+2)=y

(-8,0)

(0,8)

(0,-8)

(-4,0) and
(-2,0)

(4,0) and
(-2,0)

(0,4) and
(0,-2)

Determine the $y$ -intercept of the following equation. $\newline$ $(x-4)(x+2)=y$ $\newline$ $(-8,0)$ $\newline$ $(0,8)$ $\newline$ $(0,-8)$ $\newline$ $(-4,0)$ and $(-2,0)$ $\newline$ $(4,0)$ and $(-2,0)$ $\newline$ $(0,4)$ and $(0,-2)$

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Math Problems

Algebra 2

Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

y

-intercept of the following equation.

\newline

(x-4)(x+2)=y

\newline

(-8,0)

\newline

(0,8)

\newline

(0,-8)

\newline

(-4,0)

and

(-2,0)

\newline

(4,0)

and

(-2,0)

\newline

(0,4)

and

(0,-2)

Find y-intercept: We need to find the y-intercept of the equation $(x-4)(x+2)=y$ . The y-intercept occurs where $x=0$ . Let's substitute $x=0$ into the equation to find the $y$ -value of the y-intercept.
Substitute $x=0$ : Substitute $x=0$ into the equation: $(0-4)(0+2)=y$ .
Calculate y: Calculate the value of y: $(-4)(2)=y$ .
Perform multiplication: Perform the multiplication: $y = -8$ .
Identify y-intercept point: The y-intercept of the equation is the point where the graph crosses the y-axis, which is when $x=0$ . Therefore, the y-intercept is $(0, -8)$ .