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Determine the
y-intercept of the following equation.

(x+3)(x-5)=y

(0,-15)

(-15,0)

(-3,0) and
(5,0)

(0,-3) and
(0,5)

(3,0) and
(5,0)

(0,15)

Determine the $y$ -intercept of the following equation. $\newline$ $(x+3)(x-5)=y$ $\newline$ $(0,-15)$ $\newline$ $(-15,0)$ $\newline$ $(-3,0)$ and $(5,0)$ $\newline$ $(0,-3)$ and $(0,5)$ $\newline$ $(3,0)$ and $(5,0)$ $\newline$ $(0,15)$

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Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

y

-intercept of the following equation.

\newline

(x+3)(x-5)=y

\newline

(0,-15)

\newline

(-15,0)

\newline

(-3,0)

and

(5,0)

\newline

(0,-3)

and

(0,5)

\newline

(3,0)

and

(5,0)

\newline

(0,15)

Substitute $x$ with $0$ : To find the y-intercept of the equation, we need to substitute $x$ with $0$ in the equation $(x+3)(x-5)=y$ and solve for $y$ . $\newline$ Calculation: $y = (0+3)(0-5) = 3 \times -5 = -15$

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