Determine the y-intercept of the following equation. (x+3)(x-5)=y (3,0) and (5,0) (0,15) (-15,0) (-3,0) and (5,0) (0,-3) and (0,5) (0,-15)

Determine y-intercept: To find the y-intercept of the equation, we need to determine the value of y when x is equal to 0. This is because the y-intercept is the point where the graph of the equation crosses the y-axis, and at this point, the x-coordinate is always 0.Substitute x=0: Substitute x = 0 into the equation (x+3)(x-5)=y to find the y-intercept. y = (0+3)(0-5) y = (3)(-5) y = -15Calculate y: The y-intercept of the equation is the point (0, y), where y is the value we just calculated. Therefore, the y-intercept is (0, -15).

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Determine the
y-intercept of the following equation.

(x+3)(x-5)=y

(3,0) and
(5,0)

(0,15)

(-15,0)

(-3,0) and
(5,0)

(0,-3) and
(0,5)

(0,-15)

Determine the $y$ -intercept of the following equation. $\newline$ $(x+3)(x-5)=y$ $\newline$ $(3,0)$ and $(5,0)$ $\newline$ $(0,15)$ $\newline$ $(-15,0)$ $\newline$ $(-3,0)$ and $(5,0)$ $\newline$ $(0,-3)$ and $(0,5)$ $\newline$ $(0,-15)$

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Math Problems

Algebra 2

Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

y

-intercept of the following equation.

\newline

(x+3)(x-5)=y

\newline

(3,0)

and

(5,0)

\newline

(0,15)

\newline

(-15,0)

\newline

(-3,0)

and

(5,0)

\newline

(0,-3)

and

(0,5)

\newline

(0,-15)

Determine y-intercept: To find the y-intercept of the equation, we need to determine the value of $y$ when $x$ is equal to $0$ . This is because the y-intercept is the point where the graph of the equation crosses the y-axis, and at this point, the x-coordinate is always $0$ .
Substitute $x=0$ : Substitute $x = 0$ into the equation $(x+3)(x-5)=y$ to find the y-intercept. $\newline$ $y = (0+3)(0-5)$ $\newline$ $y = (3)(-5)$ $\newline$ $y = -15$
Calculate $y$ : The $y$ -intercept of the equation is the point $(0, y)$ , where $y$ is the value we just calculated. $\newline$ Therefore, the $y$ -intercept is $(0, -15)$ .