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Determine the
y-intercept of the following equation.

(x-3)(x-5)=y

(0,3) and
(0,5)

(15,0)

(-3,0) and
(5,0)

(0,-15)

(3,0) and
(5,0)

(0,15)

Determine the $y$ -intercept of the following equation. $\newline$ $(x-3)(x-5)=y$ $\newline$ $(0,3)$ and $(0,5)$ $\newline$ $(15,0)$ $\newline$ $(-3,0)$ and $(5,0)$ $\newline$ $(0,-15)$ $\newline$ $(3,0)$ and $(5,0)$ $\newline$ $(0,15)$

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Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

y

-intercept of the following equation.

\newline

(x-3)(x-5)=y

\newline

(0,3)

and

(0,5)

\newline

(15,0)

\newline

(-3,0)

and

(5,0)

\newline

(0,-15)

\newline

(3,0)

and

(5,0)

\newline

(0,15)

Set $x$ to $0$ : To find the y-intercept of the equation, we need to set $x$ to $0$ and solve for $y$ . The y-intercept is the point where the graph of the equation crosses the y-axis, which occurs when $x=0$ .
Substitute $x=0$ : Substitute $x=0$ into the equation $(x-3)(x-5)=y$ . $\newline$ $y = (0-3)(0-5)$
Calculate $y$ : Calculate the value of $y$ when $x=0$ . $\newline$ $y = (-3)(-5)$ $\newline$ $y = 15$
Find y-intercept: The y-intercept of the equation $(x-3)(x-5)=y$ is the point $(0,15)$ .

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