Determine the y-intercept of the following equation. (x+3)(x-1)=y (-3,0) (0,3) (3,0) and (1,0) (0,-3) (-3,0) and (1,0) (0,-3) and (0,1)

Identify y-intercept: Identify the y-intercept from the equation. The y-intercept occurs where x=0. To find the y-intercept, we substitute x=0 into the equation and solve for y.Substitute x=0: Substitute x=0 into the equation. (x+3)(x-1)=y (0+3)(0-1)=y y = 3 * (-1) y = -3Confirm y-intercept: Confirm the y-intercept. The y-intercept is the point where the graph of the equation crosses the y-axis. Since we have found y to be -3 when x is 0, the y-intercept is (0, -3).

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Determine the
y-intercept of the following equation.

(x+3)(x-1)=y

(-3,0)

(0,3)

(3,0) and
(1,0)

(0,-3)

(-3,0) and
(1,0)

(0,-3) and
(0,1)

Determine the $y$ -intercept of the following equation. $\newline$ $(x+3)(x-1)=y$ $\newline$ $(-3,0)$ $\newline$ $(0,3)$ $\newline$ $(3,0)$ and $(1,0)$ $\newline$ $(0,-3)$ $\newline$ $(-3,0)$ and $(1,0)$ $\newline$ $(0,-3)$ and $(0,1)$

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Math Problems

Algebra 2

Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

y

-intercept of the following equation.

\newline

(x+3)(x-1)=y

\newline

(-3,0)

\newline

(0,3)

\newline

(3,0)

and

(1,0)

\newline

(0,-3)

\newline

(-3,0)

and

(1,0)

\newline

(0,-3)

and

(0,1)

Identify y-intercept: Identify the y-intercept from the equation. $\newline$ The y-intercept occurs where $x=0$ . To find the y-intercept, we substitute $x=0$ into the equation and solve for $y$ .
Substitute $x=0$ : Substitute $x=0$ into the equation. $\newline$ $(x+3)(x-1)=y$ $\newline$ $(0+3)(0-1)=y$ $\newline$ $y = 3 \times (-1)$ $\newline$ $y = -3$
Confirm y-intercept: Confirm the y-intercept. $\newline$ The y-intercept is the point where the graph of the equation crosses the y-axis. Since we have found $y$ to be $-3$ when $x$ is $0$ , the y-intercept is $(0, -3)$ .