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Determine the
y-intercept of the following equation.

(-x-2)(-x-3)=y

(2,0) and
(-3,0)

(-2,0) and
(-3,0)

(0,-6)

(0,6)

(6,0)

(0,-2) and
(0,-3)

Determine the $y$ -intercept of the following equation. $\newline$ $(-x-2)(-x-3)=y$ $\newline$ $(2,0)$ and $(-3,0)$ $\newline$ $(-2,0)$ and $(-3,0)$ $\newline$ $(0,-6)$ $\newline$ $(0,6)$ $\newline$ $(6,0)$ $\newline$ $(0,-2)$ and $(0,-3)$

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Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

y

-intercept of the following equation.

\newline

(-x-2)(-x-3)=y

\newline

(2,0)

and

(-3,0)

\newline

(-2,0)

and

(-3,0)

\newline

(0,-6)

\newline

(0,6)

\newline

(6,0)

\newline

(0,-2)

and

(0,-3)

Identify y-intercept: Identify the y-intercept from the equation. $\newline$ The y-intercept occurs where $x=0$ . To find the y-intercept, we substitute $x=0$ into the equation and solve for $y$ . $\newline$ $(-x-2)(-x-3)=y$ $\newline$ $(-0-2)(-0-3)=y$ $\newline$ $(-2)(-3)=y$ $\newline$ $y=6$

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\newline

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