Determine the x-intercepts of the following equation. (-x+5)(x+3)=y (0,15) (5,0) and (-3,0) (0,5) and (0,-3) (0,-15) (15,0) (5,0) and (3,0)

Given Equation: We are given the equation (-x+5)(x+3)=y. To find the x-intercepts, we need to set y to 0 and solve for x. (-x+5)(x+3) = 0Zero Product Property: Now we have a product of two factors equal to zero. According to the zero product property, if the product of two factors is zero, then at least one of the factors must be zero. So we set each factor equal to zero and solve for x. First factor: -x + 5 = 0 Second factor: x + 3 = 0Solve First Factor: Solve the first factor for x: -x + 5 = 0 -x = -5 x = 5Solve Second Factor: Solve the second factor for x: x + 3 = 0 x = -3Final X-Intercepts: We have found the x-intercepts to be x = 5 and x = -3. These are the points where the parabola crosses the x-axis, so the coordinates of the x-intercepts are (5,0) and (-3,0).

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Determine the
x-intercepts of the following equation.

(-x+5)(x+3)=y

(0,15)

(5,0) and
(-3,0)

(0,5) and
(0,-3)

(0,-15)

(15,0)

(5,0) and
(3,0)

Determine the $x$ -intercepts of the following equation. $\newline$ $(-x+5)(x+3)=y$ $\newline$ $(0,15)$ $\newline$ $(5,0)$ and $(-3,0)$ $\newline$ $(0,5)$ and $(0,-3)$ $\newline$ $(0,-15)$ $\newline$ $(15,0)$ $\newline$ $(5,0)$ and $(3,0)$

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Math Problems

Algebra 2

Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

x

-intercepts of the following equation.

\newline

(-x+5)(x+3)=y

\newline

(0,15)

\newline

(5,0)

and

(-3,0)

\newline

(0,5)

and

(0,-3)

\newline

(0,-15)

\newline

(15,0)

\newline

(5,0)

and

(3,0)

Given Equation: We are given the equation $(-x+5)(x+3)=y$ . To find the x-intercepts, we need to set $y$ to $0$ and solve for $x$ . $\newline$ $(-x+5)(x+3) = 0$
Zero Product Property: Now we have a product of two factors equal to zero. According to the zero product property, if the product of two factors is zero, then at least one of the factors must be zero. So we set each factor equal to zero and solve for $x$ . $\newline$ First factor: $-x + 5 = 0$ $\newline$ Second factor: $x + 3 = 0$
Solve First Factor: Solve the first factor for $x$ : $-x + 5 = 0$ $-x = -5$ $x = 5$
Solve Second Factor: Solve the second factor for $x$ : $x + 3 = 0$ $x = -3$
Final X-Intercepts: We have found the x-intercepts to be $x = 5$ and $x = -3$ . These are the points where the parabola crosses the x-axis, so the coordinates of the x-intercepts are $(5,0)$ and $(-3,0)$ .