Determine the x-intercepts of the following equation. (x+3)(x-2)=y (0,6) (-6,0) (0,-6) (0,-3) and (0,2) (-3,0) and (2,0) (-3,0) and (-2,0)

Understand x-intercepts: Understand the concept of x-intercepts. The x-intercepts of an equation are the points where the graph of the equation crosses the x-axis. At these points, the value of y is 0.Set y to 0: Set y to 0 in the equation to find the x-intercepts. Since we are looking for the x-intercepts, we set y to 0 in the equation (x+3)(x-2)=y, which gives us (x+3)(x-2)=0.Solve for x: Solve the equation for x. To find the values of x that make the equation true, we need to set each factor equal to zero and solve for x. So, we have two equations: x + 3 = 0 and x - 2 = 0.Solve first equation: Solve the first equation x + 3 = 0. Subtracting 3 from both sides of the equation x + 3 = 0 gives us x = -3.Solve second equation: Solve the second equation x - 2 = 0. Adding 2 to both sides of the equation x - 2 = 0 gives us x = 2.Combine solutions: Combine the solutions to find the x-intercepts. The solutions to the equations are x = -3 and x = 2. These are the x-intercepts of the equation (x+3)(x-2)=y.

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Determine the
x-intercepts of the following equation.

(x+3)(x-2)=y

(0,6)

(-6,0)

(0,-6)

(0,-3) and
(0,2)

(-3,0) and
(2,0)

(-3,0) and
(-2,0)

Determine the $x$ -intercepts of the following equation. $\newline$ $(x+3)(x-2)=y$ $\newline$ $(0,6)$ $\newline$ $(-6,0)$ $\newline$ $(0,-6)$ $\newline$ $(0,-3)$ and $(0,2)$ $\newline$ $(-3,0)$ and $(2,0)$ $\newline$ $(-3,0)$ and $(-2,0)$

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Math Problems

Algebra 2

Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

x

-intercepts of the following equation.

\newline

(x+3)(x-2)=y

\newline

(0,6)

\newline

(-6,0)

\newline

(0,-6)

\newline

(0,-3)

and

(0,2)

\newline

(-3,0)

and

(2,0)

\newline

(-3,0)

and

(-2,0)

Understand $x$ -intercepts: Understand the concept of $x$ -intercepts. The $x$ -intercepts of an equation are the points where the graph of the equation crosses the $x$ -axis. At these points, the value of $y$ is $0$ .
Set $y$ to $0$ : Set $y$ to $0$ in the equation to find the x-intercepts. $\newline$ Since we are looking for the x-intercepts, we set $y$ to $0$ in the equation $(x+3)(x-2)=y$ , which gives us $(x+3)(x-2)=0$ .
Solve for x: Solve the equation for x. $\newline$ To find the values of $x$ that make the equation true, we need to set each factor equal to zero and solve for $x$ . $\newline$ So, we have two equations: $\newline$ $x + 3 = 0$ and $x - 2 = 0$ .
Solve first equation: Solve the first equation $x + 3 = 0$ . $\newline$ Subtracting $3$ from both sides of the equation $x + 3 = 0$ gives us $x = -3$ .
Solve second equation: Solve the second equation $x - 2 = 0$ . $\newline$ Adding $2$ to both sides of the equation $x - 2 = 0$ gives us $x = 2$ .
Combine solutions: Combine the solutions to find the x-intercepts. $\newline$ The solutions to the equations are $x = -3$ and $x = 2$ . These are the x-intercepts of the equation $(x+3)(x-2)=y$ .