Determine the x-intercepts of the following equation. (x-1)(-x-2)=y (1,0) and (-2,0) (0,-2) (0,1) and (0,-2) (1,0) and (2,0) (0,2) (2,0)

Definition of x-intercepts: The x-intercepts of a function are the points where the graph of the function crosses the x-axis. At these points, the value of y is 0.Set equation equal to zero: Set the equation equal to zero to find the x-intercepts: (x-1)(-x-2) = 0.Solve for x when y=0: To find the x-intercepts, we need to solve for x when y is equal to zero. This gives us two equations to solve: x - 1 = 0 and -x - 2 = 0.Solve first equation: Solve the first equation: x - 1 = 0. Adding 1 to both sides gives us x = 1.Solve second equation: Solve the second equation: -x - 2 = 0. Adding 2 to both sides gives us -x = 2. Multiplying both sides by -1 gives us x = -2.Identify x-intercepts: The x-intercepts of the equation are the solutions to the equations we found: x = 1 and x = -2. Therefore, the x-intercepts are (1,0) and (-2,0).

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Determine the
x-intercepts of the following equation.

(x-1)(-x-2)=y

(1,0) and
(-2,0)

(0,-2)

(0,1) and
(0,-2)

(1,0) and
(2,0)

(0,2)

(2,0)

Determine the $x$ -intercepts of the following equation. $\newline$ $(x-1)(-x-2)=y$ $\newline$ $(1,0)$ and $(-2,0)$ $\newline$ $(0,-2)$ $\newline$ $(0,1)$ and $(0,-2)$ $\newline$ $(1,0)$ and $(2,0)$ $\newline$ $(0,2)$ $\newline$ $(2,0)$

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Math Problems

Algebra 2

Write a quadratic function from its x-intercepts and another point

Full solution

Q. Determine the

x

-intercepts of the following equation.

\newline

(x-1)(-x-2)=y

\newline

(1,0)

and

(-2,0)

\newline

(0,-2)

\newline

(0,1)

and

(0,-2)

\newline

(1,0)

and

(2,0)

\newline

(0,2)

\newline

(2,0)

Definition of $x$ -intercepts: The $x$ -intercepts of a function are the points where the graph of the function crosses the $x$ -axis. At these points, the value of $y$ is $0$ .
Set equation equal to zero: Set the equation equal to zero to find the x-intercepts: $(x-1)(-x-2) = 0$ .
Solve for $x$ when $y=0$ : To find the x-intercepts, we need to solve for $x$ when $y$ is equal to zero. This gives us two equations to solve: $x - 1 = 0$ and $-x - 2 = 0$ .
Solve first equation: Solve the first equation: $x - 1 = 0$ . Adding $1$ to both sides gives us $x = 1$ .
Solve second equation: Solve the second equation: $-x - 2 = 0$ . Adding $2$ to both sides gives us $-x = 2$ . Multiplying both sides by $-1$ gives us $x = -2$ .
Identify x-intercepts: The x-intercepts of the equation are the solutions to the equations we found: $x = 1$ and $x = -2$ . Therefore, the x-intercepts are $(1,0)$ and $(-2,0)$ .